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lana66690 [7]
3 years ago
8

Which of th following is true for a parallel circuit

Chemistry
1 answer:
emmainna [20.7K]3 years ago
8 0

Answer:

  • <u><em>B. The voltage is the same across all resistors in the circuit.</em></u>

<u><em></em></u>

Explanation:

The answer choices are:

  • A.The current is the same across all resistors in the circuit.
  • B.The voltage is the same across all resistors in the circuit.
  • C. As more resistors are added, the current will decrease.
  • D. The sum of the voltage drops will equal the total voltage.

<h2>Solution</h2>

In a simple <em>parallel circuit</em>, each component (resistor) is connected directly to the battery forming different branches or pathways to the current.

Thus, the ends of each resistor receives the total potential difference or <em>voltage</em> from the battery, which is what the <em>statement B</em>. asserts. Hence, <em>statement B is true</em>.

On the other hand, the current will split among the different pathways, following Ohm's law: the greater the resistance of the resistor the lower the current. Thus, the <em>statement A is false</em>.

For a parallel circuit, the total resistance decreases as more resistors are added, which means that, again following Ohm's law, the current will increase, contradicting the statement C. Thus, the <em>statement C is false. </em>

It is in the series circuit that 'the sum of the voltage drops will equal the total voltage"; in a parallel circuit the voltage drop is the just one and the same for each resistor. Thus, the <em>statement D is false,</em>too.

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ch4aika [34]

Explanation:

Percentage ethylene by weight = 57%

Percentage propylene by weight = 43%

Suppose in 100 grams of polymer:

Mass of ethylene = 57 g

Mass of propylene = 43 g

Moles of ethylene = \frac{57 g}{28 g/mol}=2.036 mol

Moles of propylene = \frac{43g}{42g/mol}=1.024 mol

1 mole = N_A =6.022\times 10^{23} molecules/ atoms

Units of ethylene = 2.036 mol\times N_A

Units of propylene = 1.024 mol\times N_A

a) Fraction of ethylene units:

=\frac{2.036 mol\times N_A}{2.306 mol\times N_A+1.024 mol\times N_A}=\frac{509}{765}

b ) Fraction of propylene units:

=\frac{1.024mol\times N_A}{2.306 mol\times N_A+1.024 mol\times N_A}=\frac{256}{765}

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3 years ago
According to the below equation, how many moles of SO2 are required to generate 1.43×1024 water molecules?
podryga [215]
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Multiply everything on the top = 8.61x10^47
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Divide top and bottom = 7.15x10^23

Answer: 7.15x10^23 mol SO2
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Answer:

1.49×10²² atoms of H are contained in the sample

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1 mol of this has 7 moles of C, 5 moles of H, 3 moles of N and 6 moles of O

Let's determine the mass of TNT.

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So this would be the rule of three to determine the mass of TNT

3 moles of N are in 227 g of compound

0.0148 moles of N are contained in (0.0148 .227) / 3 = 1.12 g

Now we can work with the hydrogen.

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1.12 grams of TNT would contain (1.12 .5) / 227 = 0.0247 moles

Finally let's convert this moles to atoms:

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Answer:

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In order to fully comprehend the answer choices we must take a close look at the value of ΔH° = 31.05. The enthalpy change of the reaction is positive. A positive value of enthalpy of reaction implies that heat was absorbed in the course of the reaction.

If heat is absorbed in a reaction, that reaction is endothermic.

Since ∆Hreaction= ∆H products -∆H reactants, a positive value of ∆Hreaction implies that ∆Hproducts >∆Hreactants, hence the answer choice above.

5 0
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