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Olegator [25]
2 years ago
5

A 1 l container contains O2 gas at stp. if the diameter of the O2 molecule is 3.75 * 10^-10 m the mean free path of the o2 molec

ule is?
Chemistry
1 answer:
Luba_88 [7]2 years ago
8 0

The mean free path of the O₂ molecule is 5.97*10^{-5} m.

The mean free path of the O₂ molecule is calculated by the formula -

λ = \frac{1}{\sqrt{2}*\pi *d^{2}*n}

In this formula, λ represents mean free path of gas, d represents diameter and n is number of molecules.

As per the known fact, 1 mole of gas occupies 22.4 liter at STP.

So. 1 liter of O₂ gas will have number of moles = \frac{1*1}{22.4}

Number of moles = 0.045

Also, we are aware that 1 mole contains 6.02*10^{23} molecules.

So, 0.045 moles will contain number of molecules = 6.02*10^{23}*0.045

Number of molecules = 2.7*10^{22} molecules

Now, keeping the values in formula to find mean free path of gas -

λ =  \frac{1}{1.4*3.14*(3.75*10^{-10})^{2} *2.7*10^{22} }

λ = \frac{1}{16746.7}

λ = 5.97*10^{-5} m

Hence, the mean free path of the O₂ molecule is 5.97*10^{-5} m.

Learn more about calculation of mean free path -

brainly.com/question/25820669

brainly.com/question/11111618

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