Answer:
Option E) 8000
Step-by-step explanation:
It is given in the question that the number of pencils and pens in a container A are 150 and 725.
Let the number of pens and pencils in container B are x and y.
As per statement " Ratio of the number of pencils to the number of pens is 2:3"
Equation will be
Or ------(1)
Second statement says "If all pens and pencils of container B are placed in container A then ratio of pencils and pens would be 3:5"
Equation will be
5(x + 150) = 3(y + 725) [By cross multiplication]
5x + 750 = 3y + 2175
5x - 3y = 2175 - 750
5x - 3y = 1425 ------(2)
Now we put
y = 3×1425
y = 4275
Now we put y = 4275 in equation 1
x = 2850
Now (x + y) = 2850 + 4275
= 7125
Now Total number of pen and pencils in container A and container B
= 150 + 725 + 7125
= 8000
Therefore, Option E) is the answer
That’s not possible but it added to -2 it would be possible
Answer:
Step-by-step explanation:
1. Approach
Since it is given that the garden box is a rectangle, then the opposite sides are congruent. One can use this to their advantage, by setting up an equation that enables them to solve for the width of the rectangle. After doing so, one will multiply the width by the given length and solve for the area.
2. Solve for the width
It is given that the garden box is a rectangle. As per its definition, opposite sides in a rectangle are congruent. The problem gives the length and the perimeter of the rectangle, therefore, one can set up an equation and solve for the width.
Substitute,
Conver the mixed number to an improper fraction. This can be done by multiplying the "number" part of the mixed number by the denominator of the fraction. Then add the result to the numerator.
Inverse operations,
3. Solve for the area
Now that one has solved for the width of the box, one must solve for the area. This can be done by multiplying the length by the width. Since the width is a fraction, one must remember, that when multiplying an integer by a fraction, one will multiply the integer by the numerator (the top of the fraction), and then simplify by reducing the fraction, if possible. Reducing the fraction is when one divides both the numerator and the denominator by the GCF (Greatest Common Factor).
Substitute,