Answer:
3090
Step-by-step explanation:
times 1,030 to 3.
Answer:
y = one-half x + three-fourths
Step-by-step explanation:
The 2-point form of the equation of a line can be used for starters.
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
y = (11/12 -19/20)/(1/3 -2/5)(x -2/5) +19/20 . . . . fill in given values
y = ((55 -57)/60)/((5 -6)/15)(x -8/20) +19/20 . . simplify a little
y = (-1/30)/(-2/30)(x -8/20) +19/20 . . . . . . . . . . and a little more ...
y = 1/2x -4/20 +19/20
y = 1/2x +15/20
y = 1/2x +3/4 . . . . line in slope-intercept form
9514 1404 393
Answer:
- waffle $8
- hashbrowns $1.50
Step-by-step explanation:
Using w and h for the costs of a waffle and hashbrowns, respectively, we can write the equations for the purchase amounts as ...
w + h = 9.50
2w + 3h = 20.50
Subtracting twice the first equation from the second gives ...
(2w +3h) -2(w +h) = (20.50) -2(9.50)
h = 1.50 . . . . . . simplify
w = 9.50 -h = 8.00 . . . . . find w using the first equation
The cost of a waffle is $8.00; the cost of hashbrowns is $1.50.
Answer:
f(2n)-f(n)=log2
b.lg(lg2+lgn)-lglgn
c. f(2n)/f(n)=2
d.2nlg2+nlgn
e.f(2n)/(n)=4
f.f(2n)/f(n)=8
g. f(2n)/f(n)=2
Step-by-step explanation:
What is the effect in the time required to solve a prob- lem when you double the size of the input from n to 2n, assuming that the number of milliseconds the algorithm uses to solve the problem with input size n is each of these function? [Express your answer in the simplest form pos- sible, either as a ratio or a difference. Your answer may be a function of n or a constant.]
from a
f(n)=logn
f(2n)=lg(2n)
f(2n)-f(n)=log2n-logn
lo(2*n)=lg2+lgn-lgn
f(2n)-f(n)=lg2+lgn-lgn
f(2n)-f(n)=log2
2.f(n)=lglgn
F(2n)=lglg2n
f(2n)-f(n)=lglg2n-lglgn
lg2n=lg2+lgn
lg(lg2+lgn)-lglgn
3.f(n)=100n
f(2n)=100(2n)
f(2n)/f(n)=200n/100n
f(2n)/f(n)=2
the time will double
4.f(n)=nlgn
f(2n)=2nlg2n
f(2n)-f(n)=2nlg2n-nlgn
f(2n)-f(n)=2n(lg2+lgn)-nlgn
2nLg2+2nlgn-nlgn
2nlg2+nlgn
5.we shall look for the ratio
f(n)=n^2
f(2n)=2n^2
f(2n)/(n)=2n^2/n^2
f(2n)/(n)=4n^2/n^2
f(2n)/(n)=4
the time will be times 4 the initial tiote tat ratio are used because it will be easier to calculate and compare
6.n^3
f(n)=n^3
f(2n)=(2n)^3
f(2n)/f(n)=(2n)^3/n^3
f(2n)/f(n)=8
the ratio will be times 8 the initial
7.2n
f(n)=2n
f(2n)=2(2n)
f(2n)/f(n)=2(2n)/2n
f(2n)/f(n)=2
Answer:
When a line segment is bisected into 2 halves, the two halves are equal. In this case, when AB is bisected by CD, AE and BE would be equal and each point on CD should be equidistant from point A and point B. Therefore, AC = AB.