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ryzh [129]
3 years ago
9

Two___ diagrams are___ equivalent when hey have a place fro all the same items.

Mathematics
1 answer:
Volgvan3 years ago
3 0
Two Venn diagrams are not equivalent when they have a place for all the same items.
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Marla’s School has 1,030 students. Kim’s school has 3 times as many students as Sandi’s School. Write an equation to find the nu
DENIUS [597]

Answer:

3090

Step-by-step explanation:

times 1,030 to 3.

6 0
3 years ago
What is the equation of the line passing through the points (Two-fifths, StartFraction 19 Over 20 EndFraction) and (one-third, S
Neporo4naja [7]

Answer:

  y = one-half x + three-fourths

Step-by-step explanation:

The 2-point form of the equation of a line can be used for starters.

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

  y = (11/12 -19/20)/(1/3 -2/5)(x -2/5) +19/20 . . . . fill in given values

  y = ((55 -57)/60)/((5 -6)/15)(x -8/20) +19/20 . . simplify a little

  y = (-1/30)/(-2/30)(x -8/20) +19/20 . . . . . . . . . . and a little more ...

  y = 1/2x -4/20 +19/20

  y = 1/2x +15/20

  y = 1/2x +3/4 . . . . line in slope-intercept form

8 0
3 years ago
Read 2 more answers
1) At a diner, the cost for a specialty waffle and a hashbrown is $9.50. The cost for 2 specialty
klemol [59]

9514 1404 393

Answer:

  • waffle $8
  • hashbrowns $1.50

Step-by-step explanation:

Using w and h for the costs of a waffle and hashbrowns, respectively, we can write the equations for the purchase amounts as ...

  w + h = 9.50

  2w + 3h = 20.50

Subtracting twice the first equation from the second gives ...

  (2w +3h) -2(w +h) = (20.50) -2(9.50)

  h = 1.50 . . . . . . simplify

  w = 9.50 -h = 8.00 . . . . . find w using the first equation

The cost of a waffle is $8.00; the cost of hashbrowns is $1.50.

4 0
3 years ago
What is the effect in the time required to solve a prob- lem when you double the size of the input from n to 2n, assuming that t
Inga [223]

Answer:

f(2n)-f(n)=log2

b.lg(lg2+lgn)-lglgn

c. f(2n)/f(n)=2

d.2nlg2+nlgn

e.f(2n)/(n)=4

f.f(2n)/f(n)=8

g. f(2n)/f(n)=2

Step-by-step explanation:

What is the effect in the time required to solve a prob- lem when you double the size of the input from n to 2n, assuming that the number of milliseconds the algorithm uses to solve the problem with input size n is each of these function? [Express your answer in the simplest form pos- sible, either as a ratio or a difference. Your answer may be a function of n or a constant.]

from a

f(n)=logn

f(2n)=lg(2n)

f(2n)-f(n)=log2n-logn

lo(2*n)=lg2+lgn-lgn

f(2n)-f(n)=lg2+lgn-lgn

f(2n)-f(n)=log2

2.f(n)=lglgn

F(2n)=lglg2n

f(2n)-f(n)=lglg2n-lglgn

lg2n=lg2+lgn

lg(lg2+lgn)-lglgn

3.f(n)=100n

f(2n)=100(2n)

f(2n)/f(n)=200n/100n

f(2n)/f(n)=2

the time will double

4.f(n)=nlgn

f(2n)=2nlg2n

f(2n)-f(n)=2nlg2n-nlgn

f(2n)-f(n)=2n(lg2+lgn)-nlgn

2nLg2+2nlgn-nlgn

2nlg2+nlgn

5.we shall look for the ratio

f(n)=n^2

f(2n)=2n^2

f(2n)/(n)=2n^2/n^2

f(2n)/(n)=4n^2/n^2

f(2n)/(n)=4

the time will be times 4 the initial tiote tat ratio are used because it will be easier to calculate and compare

6.n^3

f(n)=n^3

f(2n)=(2n)^3

f(2n)/f(n)=(2n)^3/n^3

f(2n)/f(n)=8

the ratio will be times 8 the initial

7.2n

f(n)=2n

f(2n)=2(2n)

f(2n)/f(n)=2(2n)/2n

f(2n)/f(n)=2

5 0
3 years ago
lets say you have two line segments , ab and cd which bisects each other at point E. explain why ac = ab
Bond [772]

Answer:

When a line segment is bisected into 2 halves, the two halves are equal. In this case, when AB is bisected by CD, AE and BE would be equal and each point on CD should be equidistant from point A and point B. Therefore, AC = AB.

4 0
3 years ago
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