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3 years ago

Write a function G whose graph represents the indicated transformation of the graph f

Mathematics

1 answer:

klemol [59]3 years ago

7 0

Answer:

$G(x) = 2x^2+6$ .

Step-by-step explanation:

The given function is

$f(x) = \frac 2 3 x^2 +2$

On vertical stretch by a factor of 3, the new function G(x) is

G(x) = 3 f(x)

So, $G(x) = 3 \times ( \frac 2 3 x^2 +2)= 2x^2+6$

Hence, the required function is $G(x) = 2x^2+6$ .

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If the store purchases aan item at a wholesale cost of 3.50 per item and it is sold retail value $5.00 per item what is gross pr

Fofino [41]

((retail - cost) / retail) * 100 =
((5 - 3.5) / 5) * 100 =
(1.5/5) * 100 =
0.3 * 100 =
30% <==

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4 years ago

Simplify<br> 27^n+3 -6×3^3n+3/3^n×9^n+2

MrMuchimi

Answer:27^n+3–6*3^3n+3–n*9^n+2

Step-by-step explanation:

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3 years ago

The half-life of a radioactive element is five years. A scientist has 18 grams of the element. The equation

lianna [129]

Answer:

The equation that describes the amount of mass left after a time t of a radioactive isotope is the following:

where

is the mass of the sample at t = 0

is the half-life of the sample

For the element X in this problem,

We want to find the time t at which

So we need to re-arrange the equation making t the subject:

Step-by-step explanation:

7 0

3 years ago

Solve for u, z, y, and t:

nikitadnepr [17]

$A.\\\\\dfrac{y}{a}-b=\dfrac{y}{b}-a\qquad\text{multiply both sides by }\ ab\neq0\\\\by-ab^2=ay-a^2b\qquad\text{add}\ ab^2\ \text{to both sides}\\\\by=ay+ab^2-a^2b\qquad\text{subtract}\ ay\ \text{from both sides}\\\\by-ay=ab^2-a^2b\qquad\text{distributive}\\\\(b-a)y=ab^2-a^2b\qquad\text{divide both sides by}\ (b-a)\\\\\boxed{y=\dfrac{ab^2-a^2b}{b-a}}\to y=\dfrac{ab(b-a)}{b-a}\to\boxed{y=ab}$

$B.\\t+\dfrac{b^2}{a}=\dfrac{bt}{a}+a\qquad\text{multiply both sides by}\ a\neq0\\\\at+b^2=bt+a^2\qquad\text{subtract}\ b^2\ \text{from both sides}\\\\at=bt+a^2-b^2\qquad\text{subtract}\ bt\ \text{from both sides}\\\\at-bt=a^2-b^2\qquad\text{distributive}\\\\(a-b)t=a^2-b^2\qquad\text{divide both sides by}\ (a-b)\neq0\\\\\boxed{t=\dfrac{a^2-b^2}{a-b}}\to t=\dfrac{(a-b)(a+b)}{a-b}\to\boxed{t=a+b}$

8 0

3 years ago

The graphed line shown below is y = -4x - 12

Irina-Kira [14]

<h2>Answer:</h2>

$\boxed{y=-4x}$

<h2>Step-by-step explanation:</h2>

A linear equation is an equation of a line while a system of linear equations contains two or more linear equations that work together. A system of two linear equation has no any solution when the lines have the same slope. The graphed line shown in the Figure has an equation $y=-4x-12$ being the slope $m=-4$ . Thus, from the options the line that has the same slope is $y=-4x$ . Finally, these two lines have no any because they are parallel.

4 0

4 years ago

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