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2 years ago

Simplify. (-1/2√2)(-6√18) 18 -18 -36

Mathematics

2 answers:

olga_2 [115]2 years ago

8 0

Hey!

Your answer is solved below/above idk wherever just see in the picture.

I am Lyosha [343]2 years ago

5 0

Answer:

270

Step-by-step explanation:

$(-\frac{\sqrt{2} }{2} )(-18\sqrt{2} )18 - 18 - 36$

$\sqrt{2}$ × $9\sqrt{2}$ × 18 - 18 - 36

2 × 9 × 18 - 18 - 36

324 - 18 - 36 = 270

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The total points earned in the football game was 42. The Falcons earned 2/3 of that score. How many points did the other team sc

Elodia [21]

Step-by-step explanation:

other team earned 1/3,

42/1 * 2/3 = 84/3

so 84/3 is 28

then the Falcons = 28

so other team = total score - the Falcons

which is 42 - 28 = 14

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3 years ago

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3 years ago

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Please help problem 1, 2 and 3

laila [671]

Answer:

See attached

Step-by-step explanation:

When there is a lot of repetitive calculation to do, I like to let a spreadsheet or graphing calculator do it. The attached shows a spreadsheet that computes all the values you're asked to find.

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Note on spreadsheet formulas

When you put the formulas into the spreadsheet, make sure to fix the column number or row number of the values you're computing, as appropriate. For example, the y-values in the different columns always use the slope from the slope column (fixed), the y-intercept from that column (fixed), and the x-value from the top row (fixed). If you make the cell references relative instead of fixed, you will get wrong answers.

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2 years ago

∆ABC is an isosceles triangle. The length of CB is 12 feet 4 inches and the congruent sides are

son4ous [18]

Answer:

Answer for 2nd is option c, for 3rd is option d, for 4th is option e

Step-by-step explanation:

As we know 1 ft.=12 in.

In ΔABC

∴ The congruent sides are AB and AC respectively

CB =12 ft. 4 in.=148 in.
AB= $\frac{3}{4}$ CB =111 in. =9 ft. 3 in.
AC= $\frac{3}{4}$ CB =111 in. =9 ft. 3 in.

∵ Perimeter of ΔABC =AB+AC+CB

=9 ft. 3 in. + 9 ft. 3 in. +12 ft. 4 in.

=30 ft. 10 in.

2. In ΔDEF

∴ The congruent sides are DE and DF respectively

DE = 6 ft. 3 in. =75 in.
DF = 6 ft. 3 in. =75 in.
Let the length of FE is equal to x
0.75FE =DE =DF
0.75x = 6 ft. 3 in. =75 in.
x =100 in. =8 ft. 4 in.

∵ Perimeter of ΔDEF =DE+DF+FE

= 6 ft. 3 in. +6 ft. 3 in. +8 ft. 4 in.

= 20 ft. 10 in.

3. In ΔJKL

∴ The congruent sides are JL and KL respectively

JK = x+3
KL =4x-17
JL =6x-45
JL≅KL
4x-17 =6x-45 . . . . . . . . . . . . . . . . . . . . . . . (1)
Subracting 4x from both sides from eq 1
-17 =2x-45
Adding 45 on both the sides
28 =2x
Dividing by 2 on both sides
14 =x
JK = 14+3 =17
KL = 4×14-17 =39
JL = 6×14-45 =39

∵ The dimensions of the ΔJKL are 39,39 and 17.

6 0

3 years ago