WILL GIVE BRAINLIEST<br> A<br> B<br> C<br> D

I would like to know what 0.5-0.125q=(q-1)/4 equals out to.

Scrat [10]

Answer:

q = 2

Step-by-step explanation:

0.5-0.125q=(q-1)/4

At first, we have to multiply both the sides by 4.

4 × (0.5 - 0.125q) = q - 1

or, 2 - 0.5q = q - 1

now, we change the side by taking constant into the right side and the number into the left side.

2 + 1 = q + 0.5q

or, 3 = q (1 + 0.5)

or, 3 = 1.5 q

or, 1.5 q = 3

or, $\frac{1.5q}{1.5}$ = (3 ÷ 1.5) [Dividing both the sides by 1.5]

or, q = 2

Therefore, q = 2

8 0

3 years ago

Use your knowledge of the process of "Writing an equation given two points" to solve the following problem: A vendor has learned

nydimaria [60]

Answer: Our required linear equation would be $x+48y=148$

Step-by-step explanation:

Since we have given that

Cost of deep fried bananas on a stick = $1.00

Number of sales reached = 100 per day

Cost of deep fried bananas on a stick becomes = $2.00

Number of sales reached = 52 per day.

Let x is the number of dollars each.

Let y be the number of vendors sale.

So, we need to form the linear equation:

As we know the formula for two point slope form:

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-1=\dfrac{2-1}{52-100}(x-100)\\\\y-1=\dfrac{1}{-48}(x-100)\\\\-48(y-1)=(x-100)\\\\-48y+48=x-100\\\\-48y=x-100-48\\\\-48y=x-148\\\\x+48y=148$

Hence, our required linear equation would be $x+48y=148$

3 0

3 years ago

Which strategy best explains how to solve this problem?

photoshop1234 [79]

It is C, if it falls 14 ft. and it travels back up 7 ft. and then falls another 7 ft, and stops at the ground now you add it all up 14+7+7=28. hope that helps you.

8 0

3 years ago

Read 2 more answers

Marcellus sent four faxes to Gem. The first fax took 14 seconds to send, the second fax 19 seconds, the third 16 seconds, and th

Scrat [10]

It took 60 seconds to fax all documents to Gem

Step-by-step explanation:

The simple addition has to be done to solve the given problem

Given

total faxes = 4

Time for fax 1: $t_1 = 14\ sec$