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3 years ago

If a force acting on an object is multiplied how is product called work?

1 answer:

6 0

Work is equal to the force applied to an object multiplied by the distance it had travelled. This is work as long as the force and the direction of the distance in going in the same direction.

It is work because you're applying a force on an object to move it.

For example, work is done when you push a box across the floor, but work is not done when you lift the box up and then walk it across the room. This is because the force on the box is upwards since you're lifting it and the direction of the distance is left or right so the directions are not the same.

You might be interested in

What is the atomic number of 24 and 12 Mg

Vikki [24]

Answer:

Chromium has 24

Magnesium has 12

Krypton has 36(Not sure if they are combine)

Explanation:

4 0

3 years ago

Find the heat energy is required to change 2Kg of ice at 0 C to water at 20 C ( specific latent heat of fusion of water = 336000

katrin2010 [14]

We want to find the energy that we need to transform 2kg of ice at 0°C to water at 20°C.

We will find that we must give 840,000 Joules.

First, we must change of phase from ice to water.

We use the specific latent heat of fusion to do this, this quantity tells us the amount of energy that we need to transform 1 kg of ice into water.

So we need 336,000 J of energy to transform 1kg of ice into water, and there are 2kg of ice, then we need twice that amount of energy:

2*336,000 J = 672,000 J

Now we have 2kg of water at 0°C, and we need to increase its temperature to 20°C.

Here we use the specific heat, it tell us the amount of energy that we need to increase the temperature per mass of water by 1°C.

We know that:

specific heat of capacity of water = 4200 J/kg°C

This means that we need to give 4,200 Joules of energy to increase the temperature by 1°C of 1kg of water.

Then to increase 1°C of 2kg of water we need twice that amount:

2*4,200 J = 8,400 J

And that is for 1°C, we need to give that amount 20 times (to increase 20°C) this is:

20*8,400 J = 168,000 J

Then the total amount of energy that we must give is:

E = 672,000 J + 168,000 J = 840,000 J

If you want to learn more, you can read:

brainly.com/question/12474790

5 0

3 years ago

At 13:20 on the last Friday in September, 1989 a frantic call was received at the local police station. There had been a serious

astraxan [27]

The kinematics and conservation of momentum relationships allow to find the results for the questions about the measurements and conditions to know the accident conditions are:

1) The principles of conservation of momentum and kinematics.

2) $\theta = tan^{-1} \frac{P_{01}}{p_{02}}$

3) The factors that influence the direction and distance traveled are:

The initial speed of the vehicles

The mass of the vehicles

Pavement conditions: dry, wet, humid, with dirt or loose sand.

1) Kinematics studies the movement of bodies, they look for relationships between position, speed and acceleration.

To analyze the accident, you must answer a question such as what speed the vehicles had before the accident, this is the initial speed of each one and their directions.

When reviewing the kinematics relationships we have.

$v^2 = v_o^2 - 2 a x$

Where the acceleration is given by Newton's second law.

fr = m a

The friction force is given by the expression.

fr = μ N

fr = μ mg

Let's Substitute.

μ m g = m a

a = μ g

The friction coefficient is tabulated, for different types of rubber, pavement and wet, dry conditions, etc.

Therefore, the researcher must measure the braking distance of the vehicles, which can be taken from the mark of the tires on the road and note the condition of the pavement if it is dry or wet and the visibility of the day.

This is the speed of the vehicles just after the impact, using the law of conservation of momentum you can find the speed of the vehicles before the impact

$p_o = p_f$ \f

Where this is a vector expression, which in general is solved with the components of each directional.

Consequently to answer the questions you must use the principles of conservation of momentum and kinematics.

2) If the vehicles travel at right angles and their masses are similar, the direction after the collision in each direction.

$tan \theta = \frac{p_{01}}{p_{02}}$

$\theta = tan ^{-1} \frac{p_{01}}{p_{02}}$

3) The factors that influence the direction and distance traveled are:

The initial speed of the vehicles

The mass of the vehicles

Pavement conditions: dry, wet, humid, with dirt or loose sand.

In conclusion, using the kinematics and conservation of momentum relationships, we can find the answers to the question about measurements and conditions to know the accident conditions are:

1) The principles of conservation of momentum and kinematics.

2) $\theta = tan^{-1} \frac{P_{01}}{p_{02}}$

3) The factors that influence the direction and distance traveled are:

The initial speed of the vehicles

The mass of the vehicles

Pavement conditions: dry, wet, humid, with dirt or loose sand.

Learn more about kinematics and momentum here: brainly.com/question/17304001

5 0

3 years ago

A 7.75-l flask contains 0.482 g of hydrogen gas and 4.98 g of oxygen gas at 65°c. What is the partial pressure of oxygen in the

dimulka [17.4K]

Answer:

0.558 atm

Explanation:

We must first consider that both gases behaves like ideal gases, so we can use the following formula: PV=nRT

Then, we should consider that, whithin a mixture of gases, the total pressure is the sum of the partial pressure of each gas:

P₀ = P₁ + P₂ + ....

P₀= total pressure

P₁=P₂= is the partial pressure of each gass

If we can consider that each gas is an ideal gas, then:

P₀= (nRT/V)₁ + (nRT/V)₂ +..

Considering the molecular mass of O₂:

M O₂= 32 g/mol

And also:

R= ideal gas constant= 0.082 Lt*atm/K*mol

T= 65°C=338 K

4.98 g O₂ = 0.156 moles O₂

V= 7.75 Lt

Then:

P°O₂=partial pressure of oxygen gas= (0.156x0.082x338)/7.75

P°O₂= 0.558 atm

3 0

4 years ago

The temperature of 10 kg of a substance rises by 55oC when heated. Calculate the

guajiro [1.7K]

Given :

The temperature of 10 kg of a substance rises by 55oC when heated.

To Find :

The temperature rise when 22 kg of the substance is heated with the same quantity of heat.

Solution :

We know, change in temperature when heat is given to object is given by :

$\Delta H = m S\Delta T$

It is given that same amount of heat is given in both the cases also the substance is same.

So,

$M_1 S \Delta T_1 = M_2 S \Delta T_2\\\\10\times 55 = 22 \times \Delta T_2\\\\\Delta T_2 = 25^o\ C$

Hence, this is the required solution.

7 0

3 years ago