Answer:
0.6 Ω
Explanation:
As shown in the diagram below,
Since the resistance and the ammeter are connected in series,
(i) The same amount of current flows through them.
(ii) The sum of their individual individual voltage is equal to the total voltage of the circuit.
Applying ohm's law,
V = IR................ Equation 1
Where V = Voltage across the ammeter, I = current flowing through the ammeter, R = resistance of the ammeter.
make R the subject of the equation
R = V/I............... Equation 2
Given: V = 1.2-0.9 = 0.3 V, I = 0.5 A.
Substitute into equation 2
R = 0.3/0.5
R = 0.6 Ω
Answer:
I Would go with Kye.
Explanation:
Why i would go with her is because she has more life experience with you. She also knows you better. I would usually go with the closest one and the one who knows you the best.
Hope this helps.
<3 Have a good day!
Energy in a spring:
E = 0.5 * k * x²
k spring constant = 800 n/m
x stretch of the spring = 5 cm = 0.05 m
E = 0.5 * 800 * 0.05² = 1
The answer is 5kg m/s with the second momentum being 10 kg m/s. i took the test and it was right. hope this helps yalls