Higher frequency,higher energy,shorter wavelength
Answer:
Explanation:
We shall consider a Gaussian surface inside the insulation in the form of curved wall of a cylinder having radius equal to 3mm and unit length , length being parallel to the axis of wire .
Charge inside the cylinder = 250 x 10⁻⁹ C .
Let E be electric field at the curved surface , perpendicular to surface .
Total electric flux coming out of curved surface
= 2π r x 1 x E
= 2 x 3.14 x 3 x 10⁻³ E
According to Gauss's theorem , total flux coming out
= charge inside / ε ( 250 x 10⁻⁹C charge will lie inside cylinder )
= 250 x 10⁻⁹ / 2.5 x 8.85 x 10⁻¹² ( ε = 2.5 ε₀ = 2.5 x 8.85 x 10⁻¹² )
= 11.3 x 10³ weber .
so ,
2 x 3.14 x 3 x 10⁻³ E = 11.3 x 10³
E = 11.3 x 10³ / 2 x 3.14 x 3 x 10⁻³
= .599 x 10⁶ N /C .
Answer:
d
Explanation:
The minimum energy configuration in electrostatics states that Charges always reside on the surface of a conductor. If anyhow they were inside, an electric field would exist inside and would act to move them to the surface,
Therefore, the drawing that shows where the charges reside when they are in equilibrium is a hollowed-out "hole" in the interior of the circle, with positive signs surrounding the exterior edge. This means that the d part is the correct answer.
A. Through the direct contact of particles