Using kinematic equation,
V² - U² = -2ah (minus g is in downward direction)
At highest point, final velocity will be zero. i.e V = 0.
∴ -U² = -2ah
U = √2gh (where a = g and h = maximum height achieved)
You can find velocity if h is given to you.
F = qE + qV × B
where force F, electric field E, velocity V, and magnetic field B are vectors and the × operator is the vector cross product. If the electron remains undeflected, then F = 0 and E = -V × B
which means that |V| = |E| / |B| and the vectors must have the proper geometrical relationship. I therefore get
|V| = 8.8e3 / 3.7e-3
= 2.4e6 m/sec
Acceleration a = V²/r, where r is the radius of curvature.
a = F/m, where m is the mass of an electron,
so qVB/m = V²/r.
Solving for r yields
r = mV/qB
= 9.11e-31 kg * 2.37e6 m/sec / (1.60e-19 coul * 3.7e-3 T)
= 3.65e-3 m
<span>Answer:
We have pressure from the weight of the piston + atmospheric pressure acting on the gas
pressure from the piston...
P = F / area = mass x acceleration due to gravity / area
P = (24 kg x 9.80 m/s²) / (90 cm² x (1m/100cm)²) = 26133 N/m² = 2.61x10^4 Pa = 26.1 kPa
total pressure acting on the gas = 26+85 kPa = 111 kPa
then.. via clausius clapeyron equation..
ln(P1 / P2) = (dHvap / R) x (1 / T2 - 1 / T1)
and if I pick say.. the normal boiling point of water for P2, T2.. then...
P1 = 111 kPa
P2 = 101.325 kPa
dHvap = 40680 J/mole
R = 8.314 J/moleK
T2 = 373.15 K
T1 = ??
---> T1 = 102.46°</span>
Answer:
Explanation:
We know that the volume V for a sphere of radius r is
If we got an uncertainty 
the formula for the uncertainty of V is:
We can calculate this uncertainty, first we obtain the derivative:
And using it in the formula:
The relative uncertainty is:
Using the values for the problem:
This is, a percent uncertainty of 4.77 %
