8x +144 < 2000<br> Solve the in equation and graph

2. (15 points) Shelly has a photo that is 7 1/3 inches tall. She wants to shrink it down to fit in a picture frame that is only

Inessa [10]

A. Which reduction should she use so the picture fills as much of the frame as possible, without being too large?

Find the scale factor to get rom 7 1/3 inches to 5 1/3 inches:

5 1/3 / 7 1/3 = 0.7272

Now rewrite the fraction as decimals:

2/3 = 0.667

¾ = 0.75

5/9 = 0.555

The closest scale that would still fit the frame would be 2/3 because it is under 0.727.

B. How much extra space is there in the frame when she uses the reduction from Part A?

Multiply the original size by the scale factor to use:

7 1/3 x 2/3 = 4 8/9

Now subtract the scaled size from the original size:

7 1/3 – 4 8/9 = 2 4/9 inches extra

C. If she had a machine that could reduce by any amount, so that she could make the reduced picture fit in the frame exactly, what fraction would the reduction be?

Convert the scale from part A to a fraction:

0.72 = 72/99 which reduces to 8/11

5 0

3 years ago

Is -0.3 a rational number? is 3.14144144414444... a rational number?

Ainat [17]

I will try to make this as simple as possible.

First off, we need to know what a rational number is: A rational number is any number that can be made by dividing 2 integers. For example:

1.5 would be a rational number because 1.5 = 3/2 (3 and 2 are both integers)

With that being said, let's begin.

First off, let's start with -0.3, let's ask ourselves, can we make this number by dividing 2 integers, the answer is yes, we can, by doing $\frac{-3}{10}$ we have the equivalent of -0.3, so now we know it's a rational number.

As for the second one, it can't be a rational number because it can't be made by dividing to integers, so the answer is:

-0.3 is a rational number, but 3.14144144414444 is not.

Hope this helped! c:

3 0

3 years ago

Terry has 3 pairs of pants (black, khaki, and brown) and 4 shirts (yellow, red, blue, and white). He does not care which colors

belka [17]

Answer:

0 is the answer

Step-by-step explanation:

because colour are not pants or shirt put me in brainlist

3 0

3 years ago

Among cases of heart pacemaker malfunctions, were found to be caused by firmware, which is software programmed into the device.

alex41 [277]

Complete question is;

Among 8834 cases of heart pacemaker malfunctions, 504 were found to be caused by firmware, which is software programmed into the device. If the firmware is tested in three different pacemakers randomly selected from this batch of 8834 and the entire batch is accepted if there are no failures, what is the probability that the firmware in the entire batch will be accepted? Is this procedure likely to result in the entire batch being accepted?

Answer:

P(All three are not caused by firmware) = 83.84%

Probability that the entire batch will be accepted = 0.8384

Step-by-step explanation:

We are told that out of the 8834 cases of heart pacemaker malfunctions, 504 were found to be caused by firmware.

Thus,

Cases not caused by firmware = 8834 - 504 = 8330

So, probability of the first case not being affected by firmware is;

P(first case not caused by firmware) = 8330/8834

Also,

Probability of second case not being affected by firmware is given as;

P(second case not caused by firmware|first case not affected by firmware) = 8329/8833

Similarly,

Probability of third case not being affected by firmware is given as;

P(third case not caused by firmware|first and second not caused by firmware) = 8328/8832

Now, looking at the 3 Probabilities gotten, it is obvious that the events are not independent because the probability of occurence of one event depends on the probability of occurence of the other event.

Thus, we will make use of the general multiplication rule which is;

P(A & B) = P(B) × P(A|B)

Thus;

P(All three not caused by firmware) = P(first case not caused by firmware) × P(second case not caused by firmware|first case not affected by firmware) × P(third case not caused by firmware|first and second not caused by firmware)

Plugging in the relevant values, we have;

P(All three not caused by firmware) = (8330/8834) × (8329/8833) × (8328/8832)

P(All three are not caused by firmware) = 0.83840506679 ≈ 83.84%

6 0

3 years ago

A cable provider wants to contact customers in a particular telephone exchange to see how satisfied they are with the new digita

dusya [7]

Answer:

a) uniform

b) 1/2

c) 1/1000

Step-by-step explanation:

a) "numbers with equal probability" have a uniform distribution.

__

b) Even numbers make up 1/2 of all numbers.

__

c) There are ten such numbers in the range, so the probability is ...

10/10000 = 1/1000

7 0

3 years ago

8x +144 < 2000 Solve the in equation and graph