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Inga [223]
3 years ago
14

A club is holding a raffle. Ten thousand

Mathematics
1 answer:
Cloud [144]3 years ago
6 0

First take 10,000 * 2 = 20,000, because each of the 10,000 tickets cost 2 dollars.

3000(1/20000) + 1000(3/20000) + 500(5/20000) + 100(20/10000) = 10500/20000 = .525

Thus, each ticket is worth 52.5 cents.

Hope it helps <3

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3 years ago
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leonid [27]

Answer:

x = 72

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3 years ago
42=Wf×64 (what fraction)
Dmitry [639]
So basically 42=x times 64 or 42=64x where you want x to be represented as a fraction so just don't simplify as much

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3 years ago
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Jlenok [28]

1/2

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5 0
3 years ago
Prove the statement holds for all positive integers:<br><br> 2 + 4 + 6 + ... + 2n = n² + n
crimeas [40]

Proving a relation for all natural numbers involves proving it for n = 1 and showing that it holds for n + 1 if it is assumed that it is true for any n.

The relation 2+4+6+...+2n = n^2+n has to be proved.

If n = 1, the right hand side is equal to 2*1 = 2 and the left hand side is equal to 1^1 + 1 = 1 + 1 = 2

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= n^2 + n + 2n + 2

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= (n + 1)^2 + (n + 1)

This shows that the given relation is true for n = 1 and if it is assumed to be true for n it is also true for n + 1.

<span>By mathematical induction the relation is true for any value of n.</span>

6 0
3 years ago
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