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3 years ago

11

The amount of money Jeff earns varies directly with the number of hours he works. Jeff worked 40 hours and earned $560. What is

the constant of variation for Jeff's earnings?

2 answers:

-Dominant- [34]3 years ago

5 0

$14 is the constant variation for how much he earns

V125BC [204]3 years ago

4 0

For ever 40 hours jeff works he makes $560 that was simple
for every hour he works he makes $14

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a car traveling at a constant speed travels 175 miles in 4 hours? How many minutes will it take for the car to travel 1000 feet?

liubo4ka [24]

Answer:

0.26 minutes

Step-by-step explanation:

So if you want to solve this, you need to make all the units the same first. What you first need to work on is the rate, since what it is asking is minutes given distance in feet.

We know that there are:

5280 ft in a mile

60 minutes in an hour

We then convert the rate knowing this:

$\dfrac{174\:miles}{4\:hours}\times\dfrac{5280ft}{1\:mile}\times\dfrac{1hour}{60\:minutes} = \dfrac{918,720ft}{240\:minutes} = \dfrac{3828\:feet}{1 minute}$

In short, the car is traveling 3,828 ft every minute.

To determine how many minutes it will take for the car to travel just remember that:

$speed=\dfrac{distance\:travelled}{time}\;\rightarrow\;time=\dfrac{distance\;travelled}{speed}$

Now we plug in what we know and solve what we don't know:

$time=\dfrac{1000feet}{\dfrac{3828ft}{1minute}}\;\rightarrow\;1000ft\times\dfrac{1\:minute}{3828ft}=0.26\:minutes$

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3 years ago

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andre [41]

Answer:

$\frac{4^{21}}{5^6}$

Step-by-step explanation:

$\left(\frac{4^7}{5^2}\right)^3$

$=\frac{\left(4^7\right)^3}{\left(5^2\right)^3}$

$\left(4^7\right)^3$

$=4^{21}$

$=\frac{4^{21}}{\left(5^2\right)^3}$

$\left(5^2\right)^3$

$5^6$

$=\frac{4^{21}}{5^6}$

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