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Arisa [49]
4 years ago
10

Please Someone Help me I Need Help ASAP PLEASE

Physics
1 answer:
dimaraw [331]4 years ago
4 0
The match making one is Radiation is i think B and Convection i think is C and Conduction i think is A.  I think 1 is radiation. Because radiation is transferred between objects or an empty space. Number 2 i think is conduction Because conduction is the transfer of thermal energy between to objects touching. Number 3 i also i think is radiation because radiation transfers between objects. Number 4 i also think is conduction because the spoon was touching a hot pot that was on the stove so then the thermal energy was transferred between the two objects touching. number 5 I think is convection because convection is the transfer of energy by the movement of a fluid, such as air or water. Number 6 i think is radiation because the snake is not touching the lamp and radiation goes all across spaces. Number 7 i think is convection because convection is the movement of a fluid, such as air or water. Hope this helps sorry its so long :)      
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A hydrogen discharge lamp emits light with two prominent wavelengths: 656 nm (red) and 486 nm (blue). The light enters a flint-g
mezya [45]

Answer:

The angle between the red and blue light is 1.7°.

Explanation:

Given that,

Wavelength of red = 656 nm

Wavelength of blue = 486 nm

Angle = 37°

Suppose we need to find the angle between the red and blue light as it leaves the prism

n_{r}=1.572

n_{b}=1.587

We need to calculate the angle for red wavelength

Using Snell's law,

n_{r}\sin\theta_{i}=n_{a}\sin\theta_{r}

Put the value into the formula

1.572\sin37=1\times\sin\theta_{r}

\theta_{r}=\sin^{-1}(\dfrac{1.572\sin37}{1})

\theta_{r}=71.0^{\circ}

We need to calculate the angle for blue wavelength

Using Snell's law,

n_{b}\sin\theta_{i}=n_{a}\sin\theta_{b}

Put the value into the formula

1.587\sin37=1\times\sin\theta_{b}

\theta_{b}=\sin^{-1}(\dfrac{1.587\sin37}{1})

\theta_{b}=72.7^{\circ}

We need to calculate the angle between the red and blue light

Using formula of angle

\Delta \theta=\theta_{b}-\theta_{r}

Put the value into the formula

\Delta \theta=72.7-71.0

\Delta \theta=1.7^{\circ}

Hence, The angle between the red and blue light is 1.7°.

8 0
3 years ago
Choose the law each sentence describes. This law relates a planet's orbital period and its average distance to the Sun. The orbi
hram777 [196]

These are the Kepler's laws of planetary motion.

This law relates a planet's orbital period and its average distance to the Sun. - Third law of Kepler.

The orbits of planets are ellipses with the Sun at one focus. - First law of Kepler.

The speed of a planet varies, such that a planet sweeps out an equal area in equal time frames. - Second law of Kepler.

7 0
3 years ago
Read 2 more answers
HELP
dem82 [27]

Answer:

Explanation:

28 / 70 = 0.3857142...  = 0.39 hr

280 / 100 = 2.8 hrs.

(100 - 0) / 10 = 10 m/s²

(60 - 20) / 4 = 10 m/s²

3 0
3 years ago
if a gas has a gage pressure of 156 kpa its absolute pressure is approximately .....A... 56 kPa ....B....100 kPa.......C......25
NeX [460]

256 kPa because p-guage + p-absolute + p-atmospheric = 256

7 0
4 years ago
If you slosh the water back and forth in a bathtub at the correct frequency, the water rises first at one end and then at the ot
notka56 [123]

Answer:

Velocity(v) = frequency(f) × wavelength

f = 0.3165

Wavelength = 2×length(L)

L = 157cm

Convert the length in centimetres to metre = 1.57m

v = 2×1.57 × 0.3165

v = 0.99m/s

Approx. 1m/s

Explanation:

The velocity of a wave is the product of its frequency and it's wavelength. The frequency is already known. The wavelength is the distance between two successive wave crests which is formed by sloshing water back and forth in the bath tub. Sloshing water to one end of the tub will produce a wave crest first at that end then the other completing a cycle. The wavelength will be twice the length of the bath tub as it is the distance that both crests are formed.

Wave crest is the highest point of a wave, and in this case is where the water rises to a high point in the bath tub

7 0
3 years ago
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