To answer the two questions, we need to know two important equations involving centripetal movement:
v = ωr (ω represents angular velocity <u>in radians</u>)
a = ![\frac{v^{2}}{r}](https://tex.z-dn.net/?f=%5Cfrac%7Bv%5E%7B2%7D%7D%7Br%7D)
Let's apply the first equation to question a:
v = ωr
v = ((1800*2π) / 60) * 0.26
Wait. 2π? 0.26? 60? Let's break down why these numbers are written differently. In order to use the equation v = ωr, it is important that the units of ω is in radians. Since one revolution is equivalent to 2π radians, we can easily do the conversion from revolutions to radians by multiplying it by 2π. As for 0.26, note that the question asks for the units to be m/s. Since we need meters, we simply convert 26 cm, our radius, into meters. The revolutions is also given in revs/min, and we need to convert it into revs/sec so that we can get our final units correct. As a result, we divide the rate by 60 to convert minutes into seconds.
Back to the equation:
v = ((1800*2π)/60) * 0.26
v = (1800*2(3.14)/60) * 0.26
v = (11304/60) * 0.26
v = 188.4 * 0.26
v = 48.984
v = 49 (m/s)
Now that we know the linear velocity, we can find the centripetal acceleration:
a = ![\frac{v^{2}}{r}](https://tex.z-dn.net/?f=%5Cfrac%7Bv%5E%7B2%7D%7D%7Br%7D)
a = ![\frac{49^{2}}{0.26}](https://tex.z-dn.net/?f=%5Cfrac%7B49%5E%7B2%7D%7D%7B0.26%7D)
a = 9234.6 (m/
)
Wow! That's fast!
<u>We now have our answers for a and b:</u>
a. 49 (m/s)
b. 9.2 *
(m/
)
If you have any questions on how I got to these answers, just ask!
- breezyツ
Answer:
1.24 m/s
Explanation:
Metric unit conversion:
9.25 mm = 0.00925 m
5 mm = 0.005 m
The volume rate that flow through the single pipe is
![\dot{V} = vA = 1.45 * \pi * 0.00925^2 = 0.00039 m^3/s](https://tex.z-dn.net/?f=%5Cdot%7BV%7D%20%3D%20vA%20%3D%201.45%20%2A%20%5Cpi%20%2A%200.00925%5E2%20%3D%200.00039%20m%5E3%2Fs)
This volume rate should be constant and divided into the 4 narrower pipes, each of them would have a volume rate of
![\dot{V_n} = \dot{V} / 4 = 0.00039 / 4 = 9.74\times10^{-5} m^3/s](https://tex.z-dn.net/?f=%5Cdot%7BV_n%7D%20%3D%20%5Cdot%7BV%7D%20%2F%204%20%3D%200.00039%20%2F%204%20%3D%209.74%5Ctimes10%5E%7B-5%7D%20m%5E3%2Fs)
So the flow speed of each of the narrower pipe is:
![v_n = \frac{\dot{V_n}}{A_n} = \frac{\dot{V_n}}{\pi r_n^2}](https://tex.z-dn.net/?f=v_n%20%3D%20%5Cfrac%7B%5Cdot%7BV_n%7D%7D%7BA_n%7D%20%3D%20%5Cfrac%7B%5Cdot%7BV_n%7D%7D%7B%5Cpi%20r_n%5E2%7D)
Answer:
D. It is very small when compared to the universe
Explanation:
The Milky Way can be regarded galaxy which has Solar System in it. Milky way gives the description of appearance of galaxy from Earth, it is a hazy band of light that's been formed from the stars which can be visualized in the sky during the night, though it cannot be sorted by mere human eyes. Milky Way has existed for about 13.51 billion years with the radius of 52,850 light years. the Number of stars in milky way is about 100-400 billion. It should be noted that themilky way galaxy is a very large galaxy but It is very small when compared to the universe
.
Answer:
Given
acceleration (a) =1.5ms2
Force(F) =2100N
R. t. c mass (m) =?
Form
F=ma(divided by m both sides)
m=F/a
m=2100/105
m=1400kg
mass of car =1400kg
Answer:
32.3 m/s
Explanation:
The ball follows a projectile motion, where:
- The horizontal motion is a uniform motion at costant speed
- The vertical motion is a free fall motion (constant acceleration)
We start by analyzing the horizontal motion. The ball travels horizontally at constant speed of
![v_x = 50 m/s](https://tex.z-dn.net/?f=v_x%20%3D%2050%20m%2Fs)
and it covers a distance of
d = 165 m
So, the total time of flight of the ball is
![t=\frac{d}{v_x}=\frac{165}{50}=3.3 s](https://tex.z-dn.net/?f=t%3D%5Cfrac%7Bd%7D%7Bv_x%7D%3D%5Cfrac%7B165%7D%7B50%7D%3D3.3%20s)
In order to find the vertical velocity of the ball, we have now to analyze its vertical motion.
The vertical motion is a free-fall motion, so the ball is falling at constant acceleration; therefore we can use the following suvat equation:
![v_y = u_y +at](https://tex.z-dn.net/?f=v_y%20%3D%20u_y%20%2Bat)
where
is the vertical velocity at time t
is the initial vertical velocity
is the acceleration of gravity (taking downward as positive direction)
Substituting t = 3.3 s (the time of flight), we find the final vertical velocity of the ball: