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3 years ago

6

Believing that Nick will not be a good waiter because he is 60 years old is an example of O Stereotype O Prejudice Situational a

ttribution All of the above

1 answer:

Helen [10]3 years ago

4 0

Ya so quid fuh doil em yous

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A proton of mass 1.67 x 10-27 kg (the charge of a proton is 1.6 x 10-19 C) enters the region between two parallel plates a

Zepler [3.9K]

The answer to the question is 72773

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2 years ago

An object of mass 0.50 kg is released from the top of a building of height 8 m. The object experiences a horizontal constant for

liberstina [14]

To solve this problem with the given elements we will apply the linear motion kinematic equations. We will start by calculating the time taken, with the vertical displacement data. Subsequently, with the components of the acceleration, we will obtain the magnitude of the total acceleration, to finally obtain the horizontal displacement with the data already found.

PART A) From vertical movement we know that the acceleration is equivalent to gravity and the displacement is 8m so the time taken to carry out the route would be

$h = \frac{1}{2} gt^2$

Here,

$h = 8 m$

$g = 9.8 m/s^2$

Replacing,

$8 = 0.5 * 9.8 * t^2$

$t = 1.277 sec$

PART B) Now, Magnitude of acceleration

$a = \sqrt{a_x^2 + a_y^2}$

$a_x = \frac{1.9}{0.5} = 3.8 m/s^2$

$a_y = g = 9.8 m/s^2$

Thus, magnitude of net acceleration

$a = \sqrt{3.82^2 + 9.8^2}= 10.51 m/s^2$

PART C) Finally the displacement along horizontal direction is:

$s =v_0 t + \frac{1}{2} a t^2$

$s = 0 + \frac{1}{2} (3.8)(1.277)^2$

$s = 3.098 m$

Therefore the distance traveled along the horizontal direction before it hits the ground is 3.098m

7 0

3 years ago

List two functions of blood plasma

dexar [7]

Answer:

•Helps to maintain va proper pH in the body which supports cell function.

•Carries electrolytes such as sodium and potassium to our muscles.

8 0

3 years ago

A sprinter in a 100-m race accelerates uniformly for the first 71 m and then runs with constant velocity. The sprinter’s time fo

adoni [48]

Answer:

The acceleration of the sprinter is 1.4 m/s²

Explanation:

Hi there!

The equation of position of the sprinter is the following:

x = x0 + v0 · t + 1/2 · a · t²

Where:

x = position of the sprinter at a time t.

x0 = initial position.

v0 = initial velocity.

t = time.

a = acceleration.

Since the origin of the frame of reference is located at the starting point and the sprinter starts from rest, then, x0 and v0 are equal to zero:

x = 1/2 · a · t²

At t = 9.9 s, x = 71 m

71 m = 1/2 · a · (9.9 s)²

2 · 71 m / (9.9 s)² = a

a = 1.4 m/s²

The acceleration of the sprinter is 1.4 m/s²

3 0

4 years ago

The sides of a square increase in length at a rate of 3 m/sec. a. At what rate is the area of the square changing when the side

maks197457 [2]

The area of a square is given by:

A = s²

A is the square's area

s is the length of one of the square's sides

Let us take the derivative of both sides of the equation with respect to time t in order to determine a formula for finding the rate of change of the square's area over time:

d[A]/dt = d[s²]/dt

The chain rule says to take the derivative of s² with respect to s then multiply the result by ds/dt

dA/dt = 2s(ds/dt)

A) Given values:

s = 14m

ds/dt = 3m/s

Plug in these values and solve for dA/dt:

dA/dt = 2(14)(3)

dA/dt = 84m²/s

B) Given values:

s = 25m

ds/dt = 3m/s

Plug in these values and solve for dA/dt:

dA/dt = 2(25)(3)

dA/dt = 150m²/s

6 0

3 years ago