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2 years ago

An aircraft on its take-off run has a steady acceleration of 3 m/s2.

Physics

1 answer:

lakkis [162]2 years ago

6 0

Answer:

Acceleration(a)=3m/s^2

Time(t)=1min[1min=60s]

=1×60

=60s

Initial velocity(u)=0m/s

Velocity(v)=?

We know that,

Acceleration=v-u/t

Or,3m/s^2=v-0/60

Or,3×60=v-0

Or,v=180m/s

So,the velocity is 180m/s.

Hope,it will helpyouu!

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A light bulb, a speaker, and a toaster ovens are all examples of what in an electric circuit.

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Conductor because it creates heat.

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3 years ago

A certain light truck can go around a flat curve having a radius of 150 m with a maximum speed of 35.5 m/s. a) What is the coeff

postnew [5]

Answer:

The coefficient of friction present between the roadway and the wheels of the truck is <u>0.833</u>.

Explanation:

Given:

Radius of the curve (R) = 150 m

Maximum speed of truck (v) = 35.5 m/s

Let the coefficient of friction between the roadway and the wheels of the truck be "μ".

As the truck is moving around a circular curve. So, the force acting on it is centripetal force which acts in the radial inward direction towards the center of the circular curve.

The centripetal force acting on the truck is given as:

$F_c=\frac{mv^2}{R}$

Now, the friction between the roadway and the wheels of the truck is responsible for providing the necessary centripetal force. So, frictional force is equal to the centripetal force necessary for circular motion.

Frictional force is given as:

$f=\mu N$

Where, 'N' is the normal force. Since there is no vertical motion, the normal force is equal to weight of truck. So,

$N=mg$

Therefore, frictional force, $f=\mu mg$

Now, frictional force = centripetal force

$f=F_c\\\\\mu mg=\frac{mv^2}{R}\\\\\mu = \frac{v^2}{Rg}$

Plug in the given values and solve for 'μ'. This gives,

$\mu=\frac{(35\ m/s)^2}{(150\ m)(9.8\ m/s^2)}\\\\\mu=\frac{1225\ m^2/s^2}{1470\ m^2/s^2}\\\\\mu=0.833$

Therefore, the coefficient of friction present between the roadway and the wheels of the truck is 0.833

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3 years ago

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Answer:

Option 5.

Explanation:

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This polar nature imparts the properties like cohesion, surface tension , adhesion, etc due to the presence of hydrogen bonds in water molecule.

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3 years ago

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Answer:

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