3 years ago

A circular wire loop of radius 15.0 cm carries a current of 2.60

1 answer:

5 0

Part (a): Magnetic dipole moment

Magnetic dipole moment = IA, I = Current, A = Area of the loop
Then,
Magnetic dipole moment = 2.6*π*0.15^2 = 0.184 Am^2

Part (b): Torque acting on the loop
T = IAB SinФ, where B = Magnetic field, Ф = Angle
Then,
T = Magnetic dipole moment*B*SinФ = 0.184*12*Sin 41 = 1.447 Nm

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The electrical force on a 2-c charge is 60 n. the electric field where the charge is located is

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$F=qE$
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F=60 N
so we can re-arrange the previous formula to find the intensity of the electric field at the point where the charge is located:
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2 years ago

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Explanation: Please see the attachments below