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AfilCa [17]
3 years ago
8

Rewrite the equation by completing the square. x^2 - 4x - 32 = 0

Mathematics
1 answer:
Charra [1.4K]3 years ago
7 0
X = 8,-4
Your welcome! :)
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R={(-3, -2), (-3, 0), (-1, 2), (1, 2)} Select all numbers that are in the domain
kirza4 [7]

Answer: D: x = {-3, -1, 1}

<u>Step-by-step explanation:</u>

Domain refers to the x-values of the coordinates.

Coordinates are in the form (x, y) so we are looking for the values on the left side of the parenthesis.

(-3, -2) --> x = -3

(-3, 0)  --> x = -3  <em>already listed above so no need to list it again</em>

(-1, 2)  --> x = -1

(1, 2)  --> x = 1

the x-values are: -3, -1, & 1

so the domain is: x = {-3, -1, 1}

6 0
4 years ago
Read 2 more answers
Graph the solution to the following linear inequality in the coordinate plane.
slavikrds [6]

Answer:

Hope this helps, happy november <3

Step-by-step explanation:

8 0
3 years ago
A number written in the form a + bi is called a _____ number.
Debora [2.8K]
The correct answer to this question is letter "A. complex." A number written in the form a + bi is called a complex number. The "i" part is the imaginary part of that expression, which is complex. Imaginary numbers are complex and it's hard to evaluate, sometimes.
3 0
4 years ago
Read 2 more answers
Solve the formula for the area of a triangle A = (1/2) bh for height h
Hitman42 [59]
A = (1/2) bh for height h

2A = bh

first multiply both sides by 2 then divide both sides by b

Area of triangle = (1/2)bh

A = (1/2)bh

2A = bh

h = 2A/b

110 = 1/2(11)h

110 = 5.5h

110/5.5 = 20

The answer Is H = 20

Hope this helps (:
4 0
4 years ago
A force F=-2i+j+k acts at point A(1,5,1) on a solid which is free to turn about a fixed point Q(-1,2,1). Find the torque exerted
DerKrebs [107]

The torque exerted by the force on the body is \vec \tau = 3\,\hat{i}-2\,\hat{j} + 8\,\hat{k}.

Vectorially speaking, the torque exerted (\vec \tau) by the force on the body (\vec F) is resulted from this expression:

\vec \tau = \vec r_{QA} \times \vec F (1)

Where:

  • \vec r_{QA} - Vector distance between points A and Q.
  • \vec F - Vector force exerted at point A.

If we know that \vec r_{QA} = (2, 3, 0) and \vec F = (-2, 1, 1), then the torque is:

\vec \tau = \left|\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\2&3&0\\-2&1&1\end{array}\right|

\vec \tau = (3, -2, 8)

The torque exerted by the force on the body is \vec \tau = 3\,\hat{i}-2\,\hat{j} + 8\,\hat{k}.

To learn more on torque, we kindly invite to check this verified question: brainly.com/question/3388202

8 0
2 years ago
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