Answer:
(3,-3) (5,-3) (3,-6)
Step-by-step explanation:
I hope this helps!!
Answer:
The probability that the average of the scores of all 400 students exceeds 19.0 is larger than the probability that a single student has a score exceeding 19.0
Step-by-step explanation:
Xi~N(18.6, 6.0), n=400, Yi~Ber(p); Z~N(0, 1);
P(Xi≥19.0)=0.473
p=0.473
Yi~Ber(0.473)
Based on the Central Limit Theorem:
Then:
Based on the Central Limit Theorem:
Then:
the probability that the average of the scores of all 400 students exceeds 19.0 is larger than the probability that a single student has a score exceeding 19.0
Choice (B) is true.
For (A): 5 is not a divisor of 14, whose only divisors are 1, 2, 7, and 14.
For (B): the factors of 10 are: 1, 2, 5, and 10. The factors of 15 are: 1, 3, 5, and 15. As we can see, the only, and greatest, common factor is 5.
For (C): 3 is not a factor of 13, which is a prime number.
For (D): again, 3 is not a factor of 14.
9514 1404 393
Answer:
$(4/3)X
Step-by-step explanation:
Working 12 hours, Samia gets paid for the first 8 hours ...
8 · ($X) = $8X
For the remaining 4 hours, she is paid ...
4 · ($2X) = $8X
Then for 12 hours, she is paid a total of ...
$8X +$8X = $16X
Her average hourly pay is then ...
total pay / total hours = $16X/12 = $(4/3)X . . . average hourly pay
Answer:
Step-by-step explanation:
Given that Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl; then a second card is drawn. If the cards are drawn at random
Since with replacement, repitition of numbers is possible
Possible drawings to give sum of 8 is
(2,6) (6,2) (3,5)(5,3)(4,4)
Out of this favourable events with 5 = (3,5) (5,3)
Hence required probability =