Answer:
Pb[lead] [Xe]4f^145d^106s^26p^2
U[uranium] 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 6s^2 4e^14 5d^10 6p^6
7s^2 5f^4
This notation can be written in core notation or noble gas notation by replacing the
1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 6s^2 4e^14 5d^10 6p^6
7s^2 5f^4
with the noble gas [Rn].
[Rn]7s25f4
N[nitrogen] The full electron configuration for nitrogen is 1s^2 2s^2 2p^3.
Ti[titanium] Ti2+:[Ar]3d^2
Ti:1s^2 2s^2 2p^6 3s^2 3p^6 3d^2 4s^2
1s^2 2s^2 2p^6 3s^2 3p^5 = 17 electrons
(1) electron gain will result to a
negative charge (−), and
(2) electron loss will result to a positive charge (+),
1s^2 2s^2 2p^6 3s^2 3p^6 = 18 electrons
Hg[mercury] You should then find its atomic number is 80. It has a Xe core, so in shorthand notation, you can include [Xe]instead of
1s^2 2s^2 2p^6 3s^2 3p^6 3d^10 4s^2 4p^6 4d^10 5s^2 5p^6,
for 54 electrons. For the 6th row of the periodic table, we introduce the 4f orbitals, and proceed to atoms having occupied 5d orbitals. We, as usual, have the ns orbitals, and n=? for the 6th period?
Mercury has a regular electron configuration. It becomes:
[Xe]4f145d106s2
Explanation:
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