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Aleks [24]
3 years ago
9

A net force of 66 newtons accelerates a child at 2.0 m/s? down a smooth playground slide. What is the mass of the

Chemistry
2 answers:
RideAnS [48]3 years ago
6 0

Answer:

I think it’s 130 kg

Explanation:

makkiz [27]3 years ago
3 0

Answer:The answer is D 33

Explanation:

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In your opinion, why do you think the atomic models are not final?
julia-pushkina [17]

Answer:

because they change

Explanation:

It was based on theories and discoveries

7 0
3 years ago
PLS HELP A gas has a volume of 250 mL at 96.5 kPa. What will the pressure of the gas be if the
ella [17]

Answer:

Solve the following problems (assuming constant temperature). Assume all numbers are 3 sig figs. 1. A sample of oxygen gas occupies a volume of 250 mL at 740 torr pressure. ... the gas exert if the volume was decreased to 2.00 liters? ... A 175 mL sample of neon had its pressure changed from 75.0 kPa to 150 kPa.

Explanation:

8 0
3 years ago
A plastic bottle is closed outdoors on a cold day when the temperature is −15.0°C and is later brought inside where the temperat
Lana71 [14]

Answer:

Pressure = 1.14 atm

Explanation:

Hello,

This question requires us to calculate the final pressure of the bottle after thermal equilibrium.

This is a direct application of pressure law which states that in a fixed mass of gas, the pressure of a given gas is directly proportional to its temperature, provided that volume remains constant.

Mathematically, what this implies is

P = kT k = P / T

P1 / T1 = P2 / T2 = P3 / T3 =........= Pn / Tn

P1 / T1 = P2 / T2

P1 = 1.0atm

T1 = -15°C = (-15 + 273.15)K = 258.15K

P2 = ?

T2 = 21.5°C = (21.5 + 273.15)K = 294.65K

P1 / T1 = P2 / T2

P2 = (P1 × T2) / T1

P2 = (1.0 × 294.65) / 258.15

P2 = 1.14atm

The pressure of the gas after attaining equilibrium is 1.14atm

3 0
3 years ago
How can you use the Periodic Table of Elements to help you find information about specific elements? PLZZZ HELP MEEEEEE!!!!
elena-14-01-66 [18.8K]

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Yuh imma help-........

6 0
3 years ago
Opal is a hydrated form of silica. If a laboratory analysis of a sample of opal reveals it to contain29.2% Si, 33.3%O, and 37.5%
ZanzabumX [31]
Let us assume that there is a 100g sample of Opal. The masses of each element will be:
29.2g Si
33.3g O
37.5g H2O
Now we divide each constituent's mass by its Mr to get the moles present
Si: (29.2 / 28) = 1.04
O: (33.3 / 16) = 2.08
H2O: (37.5 / 18) = 2.08
Now we divide by the smallest number and obtain:
Si: 1
O: 2
H2O: 2
Thus, the empirical formula of Opal is:
SiO2 . 2H2O
8 0
4 years ago
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