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Ostrovityanka [42]
3 years ago
7

If f(x) = 2x - 1 and g(x) = 2x + 1, evaluate f(g(x)) when x = -3

Mathematics
1 answer:
kifflom [539]3 years ago
6 0

Answer:

f(g(-3)) = -11

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Functions
  • Function Notation
  • Composite Functions

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

f(x) = 2x - 1

g(x) = 2x + 1

<em>x</em> = -3

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em>:                                                                                                  f(g(-3))
  2. Substitute in <em>x</em> [Function g(x)]:                                                                         g(-3) = 2(-3) + 1
  3. Multiply:                                                                                                             g(-3) = -6 + 1
  4. Add:                                                                                                                   g(-3) = -5
  5. Rewrite:                                                                                                             f(-5)
  6. Substitute in <em>x</em> [Function f(x)]:                                                                           f(-5) = 2(-5) - 1
  7. Multiply:                                                                                                             f(-5) = -10 - 1
  8. Subtract:                                                                                                            f(-5) = -11
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Answer:

1)

\text{ Slope = -3}

2)

y+4=-\frac{7}{8}(x-7)

3)

y=-\frac{7}{8}x+\frac{17}{8}

Step-by-step explanation:

We want to write the equation of the line that passes through the points (7, -4) and (-1, 3) first in point-slope form and then in slope-intercept form.

1)

First and foremost, we will need to find the slope of the line. So, we can use the slope-formula:

m=\frac{y_2-y_1}{x_2-x_1}

Let (7, -4) be (x₁, y₁) and let (-1, 3) be (x₂, y₂). Substitute them into our slope formula. This yields:

m=\frac{3-(-4)}{-1-7}

Subtract. So, our slope is:

m=\frac{7}{-8}=-7/8

2)

Now, let's use the point-slope form:

y-y_1=m(x-x_1)

We will substitute -7/8 for our slope m. We will also use the point (7, -4) and this will be our (x₁, y₁). So, substituting these values yield:

y-(-4)=-\frac{7}{8}(x-7)

Simplify. So, our point-slope equation is:

y+4=-\frac{7}{8}(x-7)

3)

Finally, we want to convert this into slope-intercept form. So, let's solve for our y.

On the right, distribute:

y+4=-\frac{7}{8}x+\frac{49}{8}

Subtract 4 from both sides. Note that we can write 4 using a common denominator of 8, so 4 is 32/8. This yields:

y=-\frac{7}{8}x+\frac{49}{8}-\frac{32}{8}

Subtract. So, our slope-intercept equation is:

y=-\frac{7}{8}x+\frac{17}{8}

And we're done!

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