A.) P(t) = 130t - 0.4t^4 + 1200
The population is maximum when P'(t) = 0
P'(t) = 130 - 1.6t^3 = 0
1.6t^3 = 130
t^3 = 81.25
t = ∛81.25 = 4.3 months.
Maximum population P(t)max = 130(4.3) - 0.4(4.3)^4 + 1200 = 1,622
b.) The rabbit population will disappear when P(t) = 0
P(t) = 130t - 0.4t^4 + 1200 = 0
t ≈ 8.7 months
Answer:
Step-by-step explanation:
Refraction, rotation and transformation are rigid motions,
so, they produce congruent figures.
Dilation does not preserve side length, so it is not a congruence transformation.
Answer:
23
Step-by-step explanation:
X=20. By using the bottom sides of each figure, you can calculate that the figure on the right is 3 times larger than the similar figure on the left. This means that 2x+5=45. When solved, this yields x=20.
You can divide 950 by 19 to get the speed in ft/min:
950/19 = 50 ft/min
Hope this helps! :)
