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ohaa [14]
3 years ago
13

Determine the number of possible triangles, ABC, that can be formed given A = 30°, a = 4, and b = 10.

Mathematics
2 answers:
hichkok12 [17]3 years ago
8 0

Answer: The answer is zero.

Step-by-step explanation:

sweet [91]3 years ago
4 0

Answer:

None

Step-by-step explanation:

We are given a triangle ABC with ∠A = 30°, sides a = 4 and b = 10.

According to the 'Law of Sines- Ambiguous Case', we have,

If a < b×sinA, then no triangle is possible.

If a = b×sinA, only one triangle is possible

If a > b×sinA, two triangles are possible.

So, we have,

b×sinA = 10 × sin30 = 10 × 0.5 = 5.

Now, as

4 = a < bsinA = 5.

We get, according to the rule, no triangle is possible.

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