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2 years ago

Determine the number of possible triangles, ABC, that can be formed given A = 30°, a = 4, and b = 10.

Mathematics

2 answers:

hichkok12 [17]2 years ago

8 0

Answer: The answer is zero.

Step-by-step explanation:

sweet [91]2 years ago

4 0

Answer:

None

Step-by-step explanation:

We are given a triangle ABC with ∠A = 30°, sides a = 4 and b = 10.

According to the 'Law of Sines- Ambiguous Case', we have,

If a < b×sinA, then no triangle is possible.

If a = b×sinA, only one triangle is possible

If a > b×sinA, two triangles are possible.

So, we have,

b×sinA = 10 × sin30 = 10 × 0.5 = 5.

Now, as

4 = a < bsinA = 5.

We get, according to the rule, no triangle is possible.

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Answer:

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Step-by-step explanation:

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2 years ago

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

562 ÷ Choose... = 14 R2

Zolol [24]

Answer:

7868

Step-by-step explanation:

⇒ This can be written algebraically (with a variable x) as:

562 ÷ x = 14

⇒ Convert the division as a fraction:

$\frac{562}{x}$ = 14

⇒ Multiply both sides by 562 to get rid of the fraction and to isolate the variable x:

562 · $\frac{562}{x}$ = 14 · 562

⇒ Simplify:

x = 7868

Answer: 7868

Hope this helps! :)

4 0

3 years ago