X^2-10x+16= 0
(x-8)(x-2)=0
x = 8 or 2
Answer:
78
Step-by-step explanation:
Evaluate 6 (2 x^2 - 5) where x = -3:
6 (2 x^2 - 5) = 6 (2×(-3)^2 - 5)
Hint: | Evaluate (-3)^2.
(-3)^2 = 9:
6 (2×9 - 5)
Hint: | Multiply 2 and 9 together.
2×9 = 18:
6 (18 - 5)
Hint: | Subtract 5 from 18.
| 1 | 8
- | | 5
| 1 | 3:
6×13
Hint: | Multiply 6 and 13 together.
6×13 = 78:
Answer: 78
Yeah it would be A. because x approaching infinity is to the right of the graph, and since there is a horizontal asymptote at -3 then its correct
Answer: C) 5
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x = independent variable, y = dependent variable
Assuming this is a linear function, each increase of x by 2 leads to y going up by 10. So 10/2 = 5 is the unit increase each time x bumps up by 1.
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An alternative is to use the slope formula to get
m = (y2 - y1)/(x2 - x1)
m = (25 - 15)/(4 - 2)
m = 10/2 <--- this expression shows up again
m = 5 <---- leading to the same answer as before
So we see that the slope formula is a more drawn out method to finding the answer.
Yes. Changing the the word problem into a function, you get 30x=y.
30 = Fixed Length
x = width
y = area
No matter what width (x) you choose, the area (y) is going to be a multiple of 30 (the fixed length) because with two numbers being multiplied, if there is a fixed number that will always be the multiple and not the multiplier. For example, 10 multiplied by every number 1-10 is going to be a multiple of 10.
10x1=10, 10x2=20, 10x3=30, etc
So if Tom chooses any of these widths (x) 5, 10, or 15, y (the area) will be a multiple of 30.
30(5)=150
30(10)=300
30(15)=450
So as we double 5 to get 10, our outcome is doubled 150 to 300 and so forth. Hope this helps.
