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3 years ago

X^2-y^2=3y in polar form

Mathematics

1 answer:

Assoli18 [71]3 years ago

5 0

Answer:

Step-by-step explanation:

put x=r cos θ

y=r sin θ

r²cos²θ-r²sin²θ=3rsin θ

r²(cos²θ -sin²θ)=3r sin θ

r²cos 2θ=3rsinθ

r cos 2θ=3 sin θ

r=3sec 2θ sin θ

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saw5 [17]

Answer:

≈ 130.2 cm²

Step-by-step explanation:

A = 8×10 + π·r²

= 80 + 3.14×16

= 80 + 50.24

= 130.24

≈ 130.2 cm²

7 0

3 years ago

QUESTION 1 (3 points) Solve the following equation. Show all work. 4x² - 5 = 76

weqwewe [10]

Answer:

$x_{1} =-\frac{9}{2} \\x_{2} = \frac{9}{2}$

Step-by-step explanation:

$4x^2 = 76 + 5\\4x^2 = 81\\x^2 = \frac{81}{4}\\ x = |\frac{9}{2}|$

5 0

3 years ago

Read 2 more answers

Solve the equation for x. (find an exact answer without a calculator) e^(4x+2)-4=0.

Kay [80]

E^(4x+2)-4=0
e^(4x+2)=4
Ln (e^(4x+2))=ln 4
(4x+2)ln e=ln 4
4x+2=ln 4
4x=ln (4)-2
x=(ln (4) -2)/4

Answer: x=(ln (4)-2)/4

8 0

4 years ago

77. the volume of a cube is increasing at a rate of <img src="https://tex.z-dn.net/?f=10%20%5Cmathrm%7B~cm%7D%5E%7B3%7D%20%2F%20

Colt1911 [192]

Answer:

$\displaystyle \frac{4}{3}\text{cm}^2/\text{min}$

Step-by-step explanation:

Given

$\displaystyle \frac{dV}{dt}=10\:\text{cm}^3/\text{min}\\ \\V=s^3\\\\SA=6s^2\\\\\frac{d(SA)}{dt}=?}\:;s=30\text{cm}$

Solution

(1) Find the rate of the cube's edge length with respect to time at s=30:

$\displaystyle V=s^3\\\\\frac{dV}{dt}=3s^2\frac{ds}{dt}\\ \\10=3(30)^2\frac{ds}{dt}\\ \\10=3(900)\frac{ds}{dt}\\\\10=2700\frac{ds}{dt}\\\\\frac{10}{2700}=\frac{ds}{dt}\\\\\frac{ds}{dt}=\frac{1}{270}\text{cm}/\text{min}$

(2) Find the rate of the cube's surface area with respect to time at s=30:

$\displaystyle SA=6s^2\\\\\frac{d(SA)}{dt}=12s\frac{ds}{dt}\\ \\\frac{d(SA)}{dt}=12(30)\biggr(\frac{1}{270}\biggr)\\\\\frac{d(SA)}{dt}=\frac{360}{270}\biggr\\\\\frac{d(SA)}{dt}=\frac{4}{3}\text{cm}^2/\text{min}$

Therefore, the surface area increases when the length of an edge is 30 cm at a rate of $\displaystyle \frac{4}{3}\text{cm}^2/\text{min}$ .

6 0

2 years ago

A tuning fork moves with a velocity of 28.7 m/s with a frequency of 128 Hz. What is the wavelength of the

Lina20 [59]

B $:$:$;;$73 in drug hzsked

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3 years ago