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Bumek [7]
2 years ago
8

HELP ASAP!!!

Mathematics
1 answer:
artcher [175]2 years ago
8 0
The answer will be d but I am not fully sure.
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How do i check an equation for extraneous solutions?
Marina86 [1]
Example:

\sqrt x(x+1)=0

This suggests two solutions, x=0 and x=-1.

However, upon plugging these solutions back into the equation, you get

\sqrt0(0+1)=0(1)=0

which checks out, but

\sqrt{-1}(1-1)=0

does not because \sqrt x is defined only for x\ge0 (assuming you're looking for real solutions only). So, we call x=-1 an extraneous solution, and the complete solution set (over the real numbers) is x=0.
7 0
2 years ago
Read 2 more answers
How to translate f(x)(blue) to g(x) red?
Wittaler [7]

Answer:

<em>g(x) = </em>\sqrt{x+2}<em> - 3  </em>

Step-by-step explanation:

<em>g(x) = </em>\sqrt{x+2}<em> - 3 </em>

7 0
2 years ago
Dan has the same number of nickels and dimes in his piggy bank. If the total amount of those coins is $0.90, how many of each co
Karolina [17]

Hello There!

<u><em>n - d = 0</em></u>

<u><em>5n+10d = 90</em></u>

<u><em>----------------------</em></u>

<u><em>n-d = 0</em></u>

<u><em>n+2d = 18</em></u>

<u><em>-------------------</em></u>

<u><em>Subtract and solve for "d":</em></u>

<u><em>3d = 18</em></u>

<u><em>d = 6 (# of dimes)</em></u>

<u><em>n = d = 6 (# of nickels)</em></u>

8 0
3 years ago
this is the rust of the questions please please some one helps me because I really try my best to solve it . thank you ​
lyudmila [28]

Answer:

x = 24.

r $ \ne $ 0.

Step-by-step explanation:

2. The given equation is:

$ \frac{1}{2} (x - 4) = \frac{1}{3} x + 2 $

a) To eliminate the fractions multiply the equation throughout by the LCM of the denominators of the fraction. In this case, the LCM of (2, 3). The LCM is 6. So, multiply the entire equation by 6.

b) Half of the difference between an integer and 4 equals the sum of one - third of the integer and 2. Find the integer.

c) We have the equation:

$ \frac{1}{2} (x - 4) = \frac{1}{3} x + 2 $

Multiplying throughout by 6, we get:

$ \frac{6}{2}(x - 4) = \frac{6}{3} x + 6(2) $

$ \implies 3(x - 4) = 2x + 12 $

$ \implies 3x - 12 = 2x + 12 $

$ \implies x = 24 $

Therefore, the solution of the equation is 24.

3. The given equation is: $ ry + s = tx - m $

To solve for y:

We can rearrange the equation as:

$ ry = tx - m - s $

$ \implies y = \frac{tx - m - s}{r} $

or, $ y = \frac{tx - (m + s)}{r} $

Note that we have to impose a condition on variable $ r $. It would be that $ r $ can never be zero. i.e., $ r \ne 0 $. Otherwise, the value of $ y $ would be undefined.

4 0
3 years ago
1-2 Cos²25°÷(1-2sin²25)<br>​
shusha [124]

Answer:

have a good one

Step-by-step explanation:

6 0
2 years ago
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