(a) The work done by the person is 18.83465 kJ.
(b) The average power performed by the person during the walk is 51.4 W.
(c) The amount of food calories burnt is 4.5 Cal.
<h3>Work done by the person</h3>
The work done by the person is calculated as follows;
W = Fd
W = mgh
W = (89.2 x 9.8) x (0.162 x 133)
W = 18,834.65 J
W = 18.83465 kJ
<h3>Average power of the person</h3>
P = Fv
where;
v = (d)/t
v = (133 x 0.162)/(6 x 60 + 6)
v = (133 x 0.162)/(366)
v = 0.0588 m/s
P = (89.2 x 9.8) x 0.0588
P = 51.4 W
<h3>Amount of food calories burnt</h3>
4.1868 kJ = 1 Cal
18.83465 kJ = ?
= 4.5 Cal
Learn more about work done here: brainly.com/question/8119756
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<span>The quantity force multiplied by distance is work.Work is done when a force pushes something and the object moves some distance in the direction it’s being pushed.work = force x distance where distance traveled in the direction the force is pushing counts.The unit for rate of working also called as Power.</span>
Answer:
Period of one vibration = 0.00215 second (Approx.)
Wavelength {Is speed of sound is 343 m/s] = 0.736 m (Approx.)
Explanation:
Given:
Frequency of wave = 466 Hz
Find:
Period of one vibration
Wavelength {Is speed of sound is 343 m/s]
Computation:
Period of one vibration = 1/F
Period of one vibration = 1 / 466
Period of one vibration = 0.00215 second (Approx.)
Wavelength = Velocity / Frequency
Wavelength {Is speed of sound is 343 m/s] = 343 / 466
Wavelength {Is speed of sound is 343 m/s] = 0.736 m (Approx.)
Answer:
a) 11 m/s
b) 0.0564 s
Explanation:
Given:
m = 2100 kg
vi = 22 ..... m/s before collision
vf = 0 ......after collision to stop
Δs = 0.62 distance traveled after collision .. crumpling of truck
Part a

Part b

With the switch open, there's no current in the circuit, and therefore
no voltage drop across any of the dissipative elements (the resistor
or the battery's internal impedance). So the entire battery voltage
appears across the switch, and the voltmeter reads 12.0V .