Answer:
Second Trial satisfy principle of conservation of momentum
Explanation:
Given mass of ball A and ball B 
Let mass of ball 
and 
Final velocity of ball 
Final velocity of ball 
initial velocity of ball 
Initial velocity of ball 
Momentum after collision 
Momentum before collision 
Conservation of momentum in a closed system states that, moment before collision should be equal to moment after collision.
Now, 
Plugging each trial in this equation we get,
First Trial
momentum before collision 
moment after collision
Second Trial
moment before collision 
moment after collision
Third Trial
momentum before collision moment after collision
Fourth Trial
momentum before collision moment after collision
We can see only Trial- 2 shows the conservation of momentum in a closed system.
I think that the answer is c. good luck
"Wheel & Axle" <span>can be described as a shaft that is attached to the center of a wheel
Hope this helps!</span>
Measure the length of one side and then cube the answer. So if x represents the measurement of one side, x³ will give you the volume.
Answer:
The magnitude of the net force F₁₂₀ on the lid when the air inside the cooker has been heated to 120 °C is 
Explanation:
Here we have
Initial temperature of air T₁ = 20 °C = 293.15 K
Final temperature of air T₁ = 120 °C = 393.15 K
Initial pressure P₁ = 1 atm = 101325 Pa
Final pressure P₂ = Required
Area = A
Therefore we have for the pressure cooker, the volume is constant that is does not change
By Chales law
P₁/T₁ = P₂/T₂
P₂ = T₂×P₁/T₁ = 393.15 K× (101325 Pa/293.15 K) = 135,889.22 Pa
∴ P₂ = 135.88922 KPa = 135.9 kPa
Where Force = 
we have
Force = 
.
