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Dovator [93]
2 years ago
7

A man drops a rock into a well. (a) the man hears the sound of the splash 2.90 s after he releases the rock from rest. the speed

of sound in air (at the ambient temperature) is 336 m/s. how far below the top of the well is the surface of the water
Physics
1 answer:
zhenek [66]2 years ago
5 0
<span>In order to answer this question we must solve for distance (in this case meters). Based on the data we have we know the the rock falls 336m every second. In order to determine the total distance we must multiple this by the amount of time it took to fall. As you will see the seconds unit cancels out to leave you with meters. So, 2.9s x 336m/s = 974.4 m</span>
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A wave with a wavelength of 0.1 m moves with a speed of 0.5 m/s. What is the frequency of the wave?
kondaur [170]
Frequency= speed/ wavelength
=0.5m/s divided 0.1.m
=5.0 Hz

The answer would be letter D.
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El peso de María es de 617,4 N. Si en dos meses pierde 2,5 Kg de masa, ¿cuál será su nuevo peso?
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An object is in circular motion. How will the object behave if the centripetal force is removed
stich3 [128]

The object will sail away in a straight line ... continuing in the same direction it was going when the centripetal force stopped.

3 0
3 years ago
A total charge of 9.0 mC passes through a cross-sectional area of a nichrome wire in 3.6s. The number of electrons passing throu
Setler79 [48]
<h2>Given :</h2>

  • total charge = 9.0 mC = 0.009 C

Each electron has a charge of :

1.6 \times 10 {}^{ - 19} \:  C

For producing 1 Cuolomb charge we need :

  • \mathrm{\dfrac{1}{1.6 \times 10 {}^{ - 19} } }

  • \dfrac{10 {}^{19} }{1.6}

  • \dfrac{10\times 10 {}^{19} }{16}

  • \dfrac{100 \times 10 {}^{18} }{16}

  • \mathrm{6.24 \times 10 {}^{18}  \:  \: electrons}

Now, for producing 0.009 C of charge, the number of electrons required is :

  • 0.009 \times 6.24 \times  {10}^{18}

  • 0.05616 \times 10 {}^{18}

  • \mathrm{5.616 \times 10 {}^{16}  \:  \: electons}

_____________________________

So, Number of electrons passing through the cross section in 3.6 seconds is :

\mathrm{5.616 \times 10 {}^{16} \:  \: electrons}

Number of electrons passing through it in 1 Second is :

  • \dfrac{5.616 \times  {10}^{16} }{3.6}

  • \mathrm{1.56 \times 10 {}^{16}  \:  \: electrons}

Now, in 10 seconds the number of electrons passing through it is :

  • 10 \times  \mathrm{1.56 \times 10 {}^{16}  \:  \: }

  • \mathrm{1.56 \times 10 {}^{17}  \:  \: electrons}

_____________________________

\mathrm{ \#TeeNForeveR}

6 0
2 years ago
2. A 1750 kg car accelerates at a rate of 4.0 m/s2. How much force is the cars engine producing?
8090 [49]

Answer:

<h2>7000 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 1750 × 4

We have the final answer as

<h3>7000 N</h3>

Hope this helps you

6 0
3 years ago
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