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OlgaM077 [116]
3 years ago
8

1. How many seconds in 1 year?

Physics
2 answers:
Nezavi [6.7K]3 years ago
8 0

Answer:

3.154e+7

Explanation:

Genrish500 [490]3 years ago
6 0

Answer:

<em>Hi Todo here!! UwU</em>

Explanation:

Seconds in a year calculation. One astronomical year of a single rotation around the sun, has 365.25 days: 1 year = 365.25 days = (365.25 days) (24 hours/day) (3600 seconds/hour) = 31557600 seconds. One calendar common year has 365 days:

happy to help!

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The answer is the kinetic energy of sled B after it crash is 6439j.

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2 years ago
Who invented the wedge simple machine and why?
Lelu [443]

Answer:

Gene Sarazen began to win tournaments in 1935 with a new club he had invented that was specialized for sand play. He is hailed as the inventor of the sand wedge.

Explanation:

A wedge is a triangular shaped tool, and is a portable inclined plane, and one of the six classical simple machines. It can be used to separate two objects or portions of an object, lift up an object, or hold an object in place. It functions by converting a force applied to its blunt end into forces perpendicular (normal) to its inclined surfaces. The mechanical advantage of a wedge is given by the ratio of the length of its slope to its width.[1][2] Although a short wedge with a wide angle may do a job faster, it requires more force than a long wedge with a narrow angle.

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3 years ago
A student is swimming south applying a force of 256 N. The water exerts a westward force of 104 N. If the student has a mass of
grigory [225]

Answer:

a=2.9\ m/sec^2

Explanation:

<u>Net Forces and Acceleration</u>

The second Newton's Law relates the net force F_r acting on an object of mass m with the acceleration a it gets. Both the net force and the acceleration are vector and have the same direction because they are proportional to each other.

\vec F_r=m\vec a

According to the information given in the question, two forces are acting on the swimming student: One of 256 N pointing to the south and other to the west of 104 N. Since those forces are not aligned, we must add them like vectors as shown in the figure below.

The magnitude of the resulting force F_r is computed as the hypotenuse of a right triangle

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Note we are using only magnitudes here

\displaystyle a=\frac{F_r}{m}

\displaystyle a=\frac{276.32Nw}{95.3Kg}

\boxed{a=2.9\ m/sec^2}

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