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HACTEHA [7]
3 years ago
14

How much energy does a 75-watt light bulb consume while running for 30 minutes​

Physics
1 answer:
o-na [289]3 years ago
8 0
Dont mind that guy guys
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Debby and Ben took different routes to travel from Point A to Point E. Debby took the route along A, B, C, D, and E. Ben took th
svetlana [45]

Answer:

Ben's average speed was twice Debby's average speed.

Explanation:

Ben covered a total distance of 16 miles (10+4+2) and Debby covered 8 miles (3+2+2+1) which is half of what Ben covered. As they both reached the place in the same amount of time it tells us Ben was faster.

4 0
4 years ago
Read 2 more answers
In film photography, shutter speed is the length of time that the film is exposed to the scene you’re photographing. Similarly,
iogann1982 [59]

Answer:

a. 1/1000 sec

Explanation:

Shutter speed is the length of time that the film you’re photographing is being exposed to the scene in film photography. However, in digital photography, shutter speed is the length of time that the image sensor sees the scene the photographer is trying to capture.

For shutter speeds, the greater the denominator the higher the speed and the lower the denominator, the lower the speed.

Thus, the fastest one is option A.

6 0
3 years ago
For a point charge, how does the potential vary with distance from the point charge, r?
mr_godi [17]

For a point charge, how does the potential vary with distance from the point charge, r?

a constant

b. r.

c. 1/r.

d. 1/r^2.

e. r^2.

Answer:

The  correct option is  C

Explanation:

Generally for a point charge the electric potential is mathematically represented as

    V  =  \frac{k  Q  }{r }

Here we can deduce that the electric potential varies inversely with the distance i.e

      V  \  \alpha \  \frac{1}{r}

So

   

3 0
3 years ago
The dimension line is connected to the part being measured by _______________. A. Hidden lines B. Extension lines C. Visible lin
kondaur [170]
B: Extension Lines! You could have just searched this up on google
3 0
4 years ago
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A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket
NARA [144]

The constant acceleration of a rocket launched upward, calculated knowing that the time it takes for a bolt that falls off the side of the rocker was 6.30 seconds, is 5.68 m/s².                                                                                      

When the rocket is launched straight up with constant acceleration, the acceleration of the rocket is given by:

v_{f_{r}} = v_{i_{r}} + at    

Where:                                                              

v_{f_{r}}: is the final velocity of the rocket

v_{i_{r}}: is the initial velocity of the rocket = 0

a: is the acceleration

t: is the time

After 4 seconds, the <u>final speed of the rocket</u> will be the <u>initial speed of the bolt</u>, so:                                              

v_{f_{r}} = v_{i_{b}} = at = 4a  

When the bolt falls off the side of the rocket, the bolt hits the ground 6.30 seconds later.        

The<u> initial height of the bolt</u> will be the <u>final height of the rocket</u>, and vice-versa. With this, we can take the final height of the bolt as zero.                        

y_{f_{b}} = y_{i_{b}} + v_{i_{b}}t - \frac{1}{2}gt^{2}

0 = y_{i_{b}} + v_{i_{b}}t - \frac{1}{2}gt^{2}

y_{i_{b}} = \frac{1}{2}9.81*(6.30)^{2} - 4a*6.30 = 194.7 - 25.2a

Now, as we said above, this height (of the bolt) will be the final height of the rocket, so:

y_{f_{r}} = y_{i_{r}} + v_{i_{r}}t - \frac{1}{2}gt^{2}

194.7 - 25.2a = 0 + 0 - \frac{1}{2}a(4)^{2}    

a = \frac{194.7}{33.2} = 5.86 m/s^{2}    

   

Therefore, the acceleration of the rocket is 5.68 m/s².

You can find another example of acceleration calculation here: brainly.com/question/24589208?referrer=searchResults

I hope it helps you!                                                                              

3 0
3 years ago
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