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HACTEHA [7]
2 years ago
14

How much energy does a 75-watt light bulb consume while running for 30 minutes​

Physics
1 answer:
o-na [289]2 years ago
8 0
Dont mind that guy guys
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How much force is required to move a sled 5 meters if a person uses 60 j of work? 300N 12N 65N 30N
maksim [4K]
The answer is b 12N because
We know that<span>
W = F × d × c o s(θ)</span>
assuming theta=0 we then solve and have<span>
F=<span>W/d</span></span>
substitute known values to get:<span><span>
F=<span><span>60J/</span><span>5m</span></span>=12N</span></span>
4 0
3 years ago
Which of the following is a conductor?<br><br> copper<br> water<br> aluminum<br> all of the above
hjlf

Answer:

D all of the above

Explanation:

electricity moves easily through all of them and none of them prevent the flow of electricity

4 0
3 years ago
You will measure and record the time it takes the cart to travel certain distances, and then complete some calculations. In the
natka813 [3]

Answer:

Take the measurement of the distance (d) with a meter rule (in meters) and also measure the time (t) of the travel in seconds with a stopwatch.

question: What is the speed of the cart?

Explanation:

The speed of an object in motion is the distance covered by the object with respect to time, that is, the ratio of distance covered to the time taken to reach that distance.

Speed = distance / time

           = d (in meters m) / t (in seconds s) = m/s

6 0
2 years ago
Which of the following is the SI unit for volume
Katarina [22]
Meters for mass kilograms for volume cubic meters for density kilograms per cubic meter
3 0
3 years ago
The Assignment: A fixed quantity of an ideal gas (R 0.28 kJ/kgK; Cv-0.71kJ/kgK) is expanded from an initial condition of 35 bar,
Nikolay [14]

Answer:

Index of expansion: 4.93

Δu = -340.8 kJ/kg

q = 232.2 kJ/kg

Explanation:

The index of expansion is the relationship of pressures:

pi/pf

The ideal gas equation:

p1*v1/T1 = p2*v2/T2

p2 = p1*v1*T2/(T2*v2)

500 C = 773 K

20 C = 293 K

p2 = 35*0.1*773/(293*1.3) = 7.1 bar

The index of expansion then is 35/7.1 = 4.93

The variation of specific internal energy is:

Δu = Cv * Δt

Δu = 0.71 * (20 - 500) = -340.8 kJ/kg

The first law of thermodynamics

q = l + Δu

The work will be the expansion work

l = p2*v2 - p1*v1

35 bar = 3500000 Pa

7.1 bar = 710000 Pa

q = p2*v2 - p1*v1 + Δu

q = 710000*1.3 - 3500000*0.1 - 340800 = 232200 J/kg = 232.2 kJ/kg

7 0
3 years ago
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