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7nadin3 [17]
3 years ago
15

Which of the following is an example of an immiscible liquid?

Physics
2 answers:
GalinKa [24]3 years ago
6 0

Answer:

It is oil and water i took the quiz and got it correct !

Hope this helps you! :D

Nonamiya [84]3 years ago
4 0

Answer:

the answer is 1, oil and water

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Mercury is a metallic liquid element. It has a density of 11.3 g/cm3 . If you placed the metals listed above in mercury, which o
Ksivusya [100]

Answer:

The answer is below

Explanation:

The question is not complete since the liquid density is not given.

Archimedes principle states that a body at rest in a fluid is acted upon by an upward force known as the buoyant force. The buoyant force is equal to the weight of the fluid displaced.

An object floats when it is placed in a liquid only if the density of the object is less than the density of the liquid. Therefore those metals with density less than that of mercury would float while those with density greater than mercury would sink.

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3 years ago
During an experiment, a student moved a cell from pure water to salted water. What will most likely happen to the cell?
jarptica [38.1K]

Answer:

During an experiment, a student moves a cell from pure water to salted water. ... It will release water and shrivel. It will release water and burst.

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3 years ago
Which of the following actions does NO work?
aliya0001 [1]

Answer:

Droping a baseball

Explanation:

becasue you are useing no sort of force to drop a baseball but you are for everything else

8 0
3 years ago
Read 2 more answers
4748.36242611007 round to the nearest tenth
IceJOKER [234]

Answer:4748.36

Explanation:

3 0
3 years ago
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A researcher studying the nutritional value of a new candy places a 4.60 g sample of the candy inside a bomb calorimeter and com
blagie [28]

Answer:

4500.5 nutritional calories per gram

Explanation:

Heat lost by the new candy = heat gained by the bomb calorimeter.

Heat gained by the bomb calorimeter = c×ΔT

where c = heat capacity of the calorimeter = 32.20 KJ/K = 32200 J/K

ΔT = change in temperature = 2.69°C = 2.69 K.

Heat gained by the bomb calorimeter = 32200 × 2.69 = 86618 J

Heat lost by the new candy = heat gained by the bomb calorimeter = 86618 J = 20702.2 calories

4.60 g of the new candy lost this amount of calories by undergoing combustion,

The amount of calories per g = 20702.2 calories/4.6 g = 4500.5 calories per gram

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3 years ago
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