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tester [92]
3 years ago
15

Observer A, who is at rest in the laboratory, is studying a particle that is moving through the laboratory at a speed of v=0.8c

and determines its lifetime to be τA=129 ns. Observer A places markers in the laboratory at the locations where the particle is produced and where it decays. How far apart are those markers in the laboratory?
Physics
1 answer:
Studentka2010 [4]3 years ago
3 0

Answer:

30.96 m

Explanation:

If the particle has a lifetime of 129 ns as measured by observer A, and has a speed of 0.8c as measured by observer A, the distance between the markers will be:

d = v * Δt

v = 0.8*c = 0.8 * 3e8 = 2.4e8

Δt = ζ = 129 ns = 1.29e-7 s

d = 2.4e8 * 1.29e-7 = 30.96 m

This is the distance as measured by observer A.

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<h3>Explanation:</h3>

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A grating with 250 grooves mm is used with an incandescent light source. Assume the visible spectrum to range in wavelength from
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The number of orders that one can see the entire visible speed is 5 orders.

<h3>How to calculate the orders?</h3>

From the information given, it should be noted that the grating spacing will be:

d = (1.00 × 10^-4) / 250

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7 0
1 year ago
Just need to confirm an answer
Citrus2011 [14]

Answer:

B

Explanation:

Remark

If, when it reaches its maximum height where the PE is the greatest, that the maximum energy is when the ball is first kicked. That would mean its starting energy is 10 Joules.

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KE = 1/2 m v^2

Givens

KE = 10 J

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