First we need to convert everything into SI units.
The initial volume of the gas is (keeping in mind that
:
The initial pressure of the gas is (keeping in mind that
:
The final pressure of the gas is (keeping in mind that
)
At constant temperature, the product between pressure and volume of the gas is constant, so we can write
from which we find the final volume of the gas:
Answer:
C. A normal distribution displays the highest data scores in the middle of the distribution.
Explanation:
The statement about a normal distribution that is not true is "a normal distribution displays the highest data scores in the middle of the distribution."
Answer:
(e)-The current is doubled.
Explanation:
According to Ohm law, where I is the current, V is the voltage and R is the resistant.
If V is doubled, while R remains constant we would have
The current is doubled.
All the forces are correct except that the counter-force in the 10.0 kg block must be 2*u*m1*g + u*m2*g. The reaction force from the friction of the 5.00 kg block is u*m1*g, and the friction force from the floor is u*(m1 + m2)*g.
The 5.00 kg block must be static. T1 = u*m1*g = 0.200*5*9.80 = 9.80 N.The net force of the 10.0 kg block is 45.0 - 2*0.20*5*9.80 - 0.20*10*9.80 = 5.80 N. Thus, the acceleration of the 10.0 kg block is 5.80 / 10 = 0.580 m/s^2.
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<span>The flywheel is solid cylindrical disc. Moment of inertial = ½ * mass * radius^2
Mass = 40.0 kg
Radius = ½ * 76.0 cm = 38 cm = 0.38 meter
Moment of inertial = ½ * 41 * 0.36^2
Convert rpm to radians/second
The distance of 1 revolution = 1 circumference = 2 * π * r
The number of radians/s in 1 revolution = 2 * π
1 minute = 60 seconds
1 revolution per minute = 2 * π radians / 60 seconds = π/30 rad/s
Initial angular velocity = 500 * π/30 = 16.667 * π rad/s
170 revolutions = 170 * 2 * π = 340 * π radians
The flywheel’s initial angular velocity = 16.667 * π rad/s. It decelerated at the rate of 1.071 rad/s^2 for 48.89 seconds.
θ = ωi * t + ½ * α * t^2
θ = 16.667 * π * 48.89 + ½ * -1.071 * 48.89^2
2559.9 - 1280
θ = 1280 radians</span>