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tester [92]
3 years ago
15

Observer A, who is at rest in the laboratory, is studying a particle that is moving through the laboratory at a speed of v=0.8c

and determines its lifetime to be τA=129 ns. Observer A places markers in the laboratory at the locations where the particle is produced and where it decays. How far apart are those markers in the laboratory?
Physics
1 answer:
Studentka2010 [4]3 years ago
3 0

Answer:

30.96 m

Explanation:

If the particle has a lifetime of 129 ns as measured by observer A, and has a speed of 0.8c as measured by observer A, the distance between the markers will be:

d = v * Δt

v = 0.8*c = 0.8 * 3e8 = 2.4e8

Δt = ζ = 129 ns = 1.29e-7 s

d = 2.4e8 * 1.29e-7 = 30.96 m

This is the distance as measured by observer A.

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Wolfgang pauli hypothesized an exclusion principle. This principle says two electrons in an atom cannot have the same what?.
PilotLPTM [1.2K]

No two electrons can have the same set of quantum numbers .

<h3>What is Wolfgang Pauli hypothesized an exclusion principle?</h3>

Pauli made a significant advance when he proposed the notion of adding a fourth quantum number to the three that were previously used to represent the quantum state of an electron. Physically speaking, the first three quantum numbers made sense since they had to do with how the electron moved about the nucleus.

The following rule was developed by Austrian physicist Wolfgang Pauli. The quantum numbers of any two electrons cannot be identical.

To put it another way, no two electrons can be in the same state. The Pauli exclusion principle is the name given to this proposition since it forbids electrons from being in the same state.

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2 years ago
A heat engine operates between two reservoirs at 300K. During each cycle, it absorbs 200 calories from the high temperature rese
yanalaym [24]

(a) Zero

The maximum efficiency (Carnot efficiency) of a heat engine is given by

\eta=1-\frac{T_C}{T_H}

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T_C is the low-temperature reservoir

T_H is the high-temperature reservoir

For the heat engine in the problem, we have:

T_C = 300K

T_H = 300K

Therefore, the maximum efficiency is

\eta=1-\frac{300}{300}=0

(b) Zero

The efficiency of a heat engine can also be rewritten as

\eta = \frac{W}{Q_H}

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Q_H is the heat absorbed from the high-temperature reservoir

In this problem, we know

\eta=0

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5 0
3 years ago
3.
lozanna [386]

The force of gravity produces acceleration in all C. freely falling objects and this is known as acceleration due to gravity

Explanation:

A body is said to be in free fall when there is only one force acting on the body: the force of gravity.

Gravity is a force that acts downward, i.e. towards the Earth's centre.

If we are near the Earth's surface, the magnitude of the force of gravity on a body is given by

F=mg

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m is the mass of the body

g is known as the acceleration of gravity , whose value near the Earth's surface is 9.8 m/s^2).

We can apply Newton's second law on an object in free-fall, to find its acceleration. In fact, we have:

F=ma

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Solving for the acceleration,

a=\frac{F}{m}

And substituting F,

a=\frac{mg}{m}=g=9.8 m/s^2

Therefore, every object in free-fall accelerates at 9.8 m/s^2 towards the ground.

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8 0
3 years ago
Un hamster esta sentado sobre un tocadisco cuya rapidez angular es constante si el hamster se mueve a un punto localizado al dob
kotegsom [21]

Answer:

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The disk is moving with constant angular velocity, let's call it \omega.

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In this problem, the object is moved at a distance twice as far as the initial point, so

r' = 2r

Therefore, the new linear velocity is

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So, the velocity has doubled, and the correct answer is

b) se duplica

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3 years ago
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