Answer:
a
Step-by-step explanation: ya boi got at least a 90 in all classes
1300+22=1322 1322+6=1328 answer: 1328
Greetings!
"<span>What is the general process for solving an equation with one variable?"...
Typically when solving an equation with one variable, your objective is to
isolate the variable on one side of the equation. This can be done adding/subtracting number to cancel them out on one side. You can also multiply/divide coefficients in order to isolate a variable.
Example:</span>

<span>Add
-4 to both sides to isolate the variable.
</span>

<span>
Simplify.
</span>

Divide both sides by
2 to isolate the variable on one side.


Hope this helps.
-Benjamin
Answer: 0.025
Step-by-step explanation:
Given : A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between the interval [48.0 minutes, 58.0 minutes].
The probability density function :-

Now, the probability that a given class period runs between 50.25 and 50.5 minutes is given by :-
![\int^{50.5}_{50.25}\ f(x)\ dx\\\\=\int^{50.5}_{50.25}\ \dfrac{1}{10}\ dx\\\\=\dfrac{1}{10}|x|^{50.5}_{50.25}\\\\=\dfrac{1}{10}\ [50.5-50.25]=\dfrac{1}{10}\times(0.25)=0.025](https://tex.z-dn.net/?f=%5Cint%5E%7B50.5%7D_%7B50.25%7D%5C%20f%28x%29%5C%20dx%5C%5C%5C%5C%3D%5Cint%5E%7B50.5%7D_%7B50.25%7D%5C%20%5Cdfrac%7B1%7D%7B10%7D%5C%20dx%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B10%7D%7Cx%7C%5E%7B50.5%7D_%7B50.25%7D%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B10%7D%5C%20%5B50.5-50.25%5D%3D%5Cdfrac%7B1%7D%7B10%7D%5Ctimes%280.25%29%3D0.025)
Hence, the probability that a given class period runs between 50.25 and 50.5 minutes =0.025
Similarly , the probability of selecting a class that runs between 50.25 and 50.5 minutes = 0.025
Answer:
2
Step-by-step explanation:
ok so let's start
were starting off with -3/4 and were adding 2 3/4 to that and it's equal to 2 3/4 subtract 3/4
-3/4 + 2 3/4 = 2 3/4 - 3/4
2 3/4 - 3/4 = 2
-3/4 + 2 3/4 = 2
it's 2 my dude or girl i don't know