A prop for the theater club's play is constructed as a cone topped with a half-sphere. What is the volume of the prop? Round to
the nearest tenth of a cubic inch. Use 3.14 to approximate Pi.
Height (Cone): 15 In . Radius (flat part of the cone): 7 In
Thanks in advance for anyone who answers! <3
Height (Cone): 15 In . Radius (flat part of the cone): 7 In
Thanks in advance for anyone who answers! <3
1 answer:
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Answer:
x = 67.50 ft
Step-by-step explanation:
Consider, ΔMAB and ΔMNP,
∠M = ∠M (Common)
Given AB║NP and let MN as transversal,
∠MAB = ∠MNP (alternate angle)
Also, Given AB║NP and let MP as transversal,
∠MBA = ∠MPN (alternate angle)
Therefore, ΔMAB ≅ ΔMNP (By AAA similarity )
Thus, by CPCT,
consider first two ratios,
Substitute the values, MA = MN - AN = 49.5 ft
On solving for x , we get, x = 67.50 ft
Thus, value of x is 67.50 ft