3 years ago

Please can you help me out on this question posted picture

1 answer:

6 0

When atleast one dice shows a 6 the possible outcomes will be:
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
(1,6), (2,6), (3,6), (4,6), (5,6)

Thus there are 11 total possible outcomes.

Among these outcomes, the sum of numbers greater than or equal to 9 can be obtained from:
(6,3), (6,4), (6,5), (6,6), (3,6), (4,6), (5,6)

This means there are 7 outcomes with sum greater than or equal to 9.

Thus, Probability of rolling a number greater than or equal to 9 with atleast one dice showing a 6 = 9/11

So, option A gives the correct answer

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What are the zeros of the parabola whose equation is y = x2 + 8x + 15

Sedbober [7]

9514 1404 393

Answer:

(1) -5 and -3

Step-by-step explanation:

Descarte's rule of signs tells you the lack of sign changes among the coefficients means there are <em>no positive real roots</em>. That eliminates all answer choices except the first one.

If you want to go to the trouble, you can factor the equation:

y = (x +3)(x +5)

These factors are zero when x = -5 and x = -3.