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Iteru [2.4K]
3 years ago
14

Please can you help me out on this question posted picture

Mathematics
1 answer:
mixer [17]3 years ago
6 0
When atleast one dice shows a 6 the possible outcomes will be:
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
(1,6), (2,6), (3,6), (4,6), (5,6)

Thus there are 11 total possible outcomes.

Among these outcomes, the sum of numbers greater than or equal to 9 can be obtained from:
(6,3), (6,4), (6,5), (6,6), (3,6), (4,6), (5,6)

This means there are 7 outcomes with sum greater than or equal to 9. 

Thus, Probability of rolling a number greater than or equal to 9 with atleast one dice showing a 6 = 9/11

So, option A gives the correct answer
You might be interested in
Given: m arc AB = 4x, m arc BC = 3x<br> m arc CD = 2x, m arc DA = 3x<br> Find: m∠APB
Vitek1552 [10]

Answer:

a > m/bp

Step-by-step explanation:

flip the equation

abp > m

divide both sides with bp

abp/bp > m/bp

a > m/bp

3 0
3 years ago
Read 2 more answers
Hii! I need some help, would anyone mind helping me?
Kisachek [45]

Step-by-step explanation:

{x}^{2}  - 14x  - 25 {y}^{2}  + 100y = 76

Factor by grouping,

( {x}^{2}  - 14x)   - (25 {y}^{2}  - 100y) = 76

Complete the square, with the x variables,

( {x}^{2}  - 14x + 49)  - (25 {y}^{2}  - 100y) = 125

Factor out 25 for the y variables

( {x}^{2}  - 14x + 49) - 25( {y}^{2}  - 4y) = 125

Complete the square

( {x}^{2}  - 14x + 49) - 25( {y}^{2}  - 4y + 4) = 25

Simplify the perfect square trinomial

(x - 7) {}^{2}  - 25(y - 2) {}^{2}  = 25

Make the right side be 1 so divide everything by 25.

\frac{(x - 7) {}^{2} }{25}  -  (y - 2) {}^{2}  = 1

Here our center is (7,2).

8 0
2 years ago
The polynomial p(x)=x^3+7x^2-36p(x)=x 3 +7x 2 −36p, left parenthesis, x, right parenthesis, equals, x, cubed, plus, 7, x, square
Iteru [2.4K]

Answer:

(x-2)(x+3)(x+6)

Step-by-step explanation:

Given the polynomial function p(x)=x^3+7x^2-36

We are to write it as a product of its linear factor

Assuming the value of x that will make the polynomial p(x) to be zero

Let x = 2

P(2) = 2³+7(2)²-36

P(2) = 8+7(4)-36

P(2) = 8+28-36

P(2) = 0

Since p(2) = 0 hence x-2 is one of the linear factors

Also assume x = -3

P(-3) = (-3)³+7(-3)²-36

P(-3) = -27+7(9)-36

P(-3) = -27+63-36

P(-3) = 36-36

P(-3) = 0

Since p(-3) = 0, hence x+3 is also a factor

The two linear pair are (x-2)(x+3)

(x-2)(x+3) = x²+3x-2x-6

(x-2)(x+3) = x²+x-6

To get the third linear function, we will divide x^3+7x^2-36 by x²+x-6 as shown in the attachment.

x^3+7x^2-36/x²+x-6 = x+6

Hence the third linear factor is x+6

x^3+7x^2-36 = (x-2)(x+3)(x+6)

8 0
3 years ago
Read 2 more answers
Help with proofs please
alexandr402 [8]

Answer:

D. Subtraction Property of Equality

Step-by-step explanation:

Hope it helps.

8 0
2 years ago
Which angles are acute?
mixer [17]

angles x y z are all acute because they are less than 90 degrees

]

4 0
3 years ago
Read 2 more answers
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