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lana66690 [7]
3 years ago
9

The vertical columns in the periodic table are called _____________. families periods rows

Physics
2 answers:
denpristay [2]3 years ago
5 0

Answer:

the answer is families

Explanation:

bonufazy [111]3 years ago
4 0

Answer:

families

Explanation:

periods are horizontal

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A truck is speeding up as it travels on an interstate. The truck's momentum (in kg · m/s) is proportional to the truck's speed (
muminat

Answer:

At the moment, the truck's momentum (in kg · m/s)  is 2200 times as large as the truck's speed (in m/s).

This means that as the truck travels, the truck's momentum (in kg · m/s) is always 2200 times as large as the truck's speed (in m/s).

If the truck is travelling at 16 m/s, the truck's momentum is 35200 kg · m/s.

Explanation:

From the question,

The truck's momentum (in kg · m/s) is proportional to the truck's speed (in m/s).

Let the truck's momentum be P and the truck's speed be v,

Then  we can write that

P∝v

Then,

P = kv

Where k is the proportionality constant

From the question,

At some moment the truck's momentum is 50600 kg · m/s and the truck's speed is 23 m/s,

To determine how many times the truck's speed is as large as the truck's momentum at this moment, we will divide the truck's momentum by the speed, that is

50600 ÷ 23 = 2200

Hence, at the moment, the truck's momentum (in kg · m/s)  is 2200 times as large as the truck's speed (in m/s).

Since, dividing the truck's momentum by the truck's speed gives the proportionality constant k (that is, P/v = k), then

This means that as the truck travels, the truck's momentum (in kg · m/s) is always 2200 times as large as the truck's speed (in m/s).

From

P = kv

Then, k = P/v

At a moment, P = 50600 kg · m/s and v = 23 m/s

∴ k = 50600 kg · m/s ÷ 23 m/s = 2200 kg

k = 2200 kg

To determine the truck's momentum if the truck is traveling at 16 m/s

From

P = kv

k = 2200 kg

v = 16 m/s

∴ P = 2200 kg × 16 m/s

P = 35200 kg · m/s

Hence, if the truck is travelling at 16 m/s, the truck's momentum is 35200 kg · m/s.

3 0
3 years ago
How strong is the attractive force between a glass rod with a 0.700μC0.700μC charge and a silk cloth with a –0.600μC–0.600μC cha
lisov135 [29]

Answer:

0.2625 N/C

Explanation:

Force of attraction = \frac{K\timesQ_1\times Q_2}{R^2}

where Q₁ and Q₂ are charges and R is distance between charges.K is a constant equal to 9 x 10⁹.

= \frac{9\times10^9\times.7\times10^{-6}\times.6\times10^{-6}}{(12\times10^{-2})^2}

= 0.2625 N/C

4 0
3 years ago
assuming that the seafloor is spreading at a rate of 1.3cm/yr, calculate how long it took africa's west coast to move 2400 kn aw
Verdich [7]

Answer: 184,615,384.6 years

Explanation:

This problem can be solve by the following equation:

V=\frac{d}{t} (1)

Where:

V=1.3 \frac{cm}{year} \frac{1 km}{100000 cm}=0.000013 \frac{km}{year} is the spreading rate of the seafloor, its velocity

d=2400 km is the distance the Africa's west coast moved at this rate

t is the time it took to the coast to move the descibed distance

Isolating t from (1):

t=\frac{d}{V} (2)

t=\frac{2400 km}{0.000013 \frac{km}{year}} (3)

Finally:

t=184,615,384.6 years This is the time it took to the Africa's west coastto  move away from the Mid atlantic ridge.

3 0
2 years ago
Can someone please help me with history.
tamaranim1 [39]

Answer:

Yes my name is Axelrod I can help you

6 0
3 years ago
Which statements describe a closed circuit? Check all that apply. Bulbs will shine. Bulbs will not shine. The circuit is incompl
vaieri [72.5K]

Bulbs will shine.

The circuit is complete.

Charges flow.

4 0
3 years ago
Read 2 more answers
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