Answer:
-2 ms⁻²
Explanation:
Here,
Initial velocity (u) = 15 ms⁻¹
Final velocity (v) = 5 ms⁻¹
Time (t) = 5 seconds
Acceleration (a) = ?
<u>Formula: </u>
a = (v-u)/t
⇒ a = (5-15)/5
⇒ a = -10/5
⇒a = -2
∴acceleration of the the car was -2 ms⁻²
<u>Note:</u>
The answer is negative because of decreasing the velocity . That means it is deceleration.
Refer to the diagram shown below.
h = height of the girl above water when she lets go of the rope.
The launch velocity is 22.5 m/s at 35° to the horizontal. Therefore the vertical component of the velocity is
v = 22.5 sin(35°) = 12.9055 m/s.
The time of flight is t = 1.10 s before the girl hits the surface of the water at a height of -h.
Therefore
-h = (12.9055 m/s)*(1.10 s) - (1/2)*(9.8 m/s²)*(1.10 s)²
-h = 8.267 m
= 8.3 m (nearest tenth)
Answer:
When the girl let go of the rope, she was about 8.3 m above the surface of the water.
Answer:
Explanation:
stiffness k = 160
m = 10
angular frequency ω = 
= 
= 4
ω = 4
Let x = 4 - A sinωt
when t = 0
x = 4 in
when t = 2 s , x = - 4
- 4 = 4 - A sinωt
8 = A sin 4 x 2
8 = A sin8
A = 8 / sin 8
= 8 / .989
= 8.09 in .
x = 4 - A sinωt
dx / dt = - Aω cosωt
v = - Aω cosωt
for t = 0
v = - Aω
= - 8.09 x 4
= - 32.36 in / s
initial velocity v = - 32.36 in /s
displacement x for t = 4s
x = 4 - 8.09 sin 4 x 4
= 4 - 8.09 sin 16
= 4 - 8.09 x - .2879
= 4 + 2.33
= 6.33 in.
c ) Amplitude of vibration A = 8.09 in .as calculated above .
Answer:
I think the answer is d. Earth's tilt produces unequal periods of daylight and climate patterns called seasons.