Which equation is used to calculate the electric potential in an electric field from a point charge?

What is the momentum of a 4 kg object moving west at 4 m/s?*

Grace [21]

Answer:

16kg*m/s west

Explanation:

P=M*V

Momentum= Mass time velocity, plug it into the formula,

M is 4 and V is 4, 4*4=16, and since the object is moving west its going to be west.

basically saying in simpler terms,

16=4*4

4 0

3 years ago

Colors seen on the cover of our physics book result from color Group of answer choices addition. subtraction. either of these ne

Alex Ar [27]

Colors seen on the cover of our physics book result from color is due to Subtraction.

What is physics of color subtraction?

Some visible spectrum wavelengths are intentionally removed during the subtraction procedure.
For instance, the yellow filter transmits the green and red colors while blocking the blue.
Red and blue are transmitted while the green is blocked by the magenta filter.
Blue and green are transmitted while red is blocked by the cyan filter.
Subtractive mixing gets its name from the fact that when colors are mixed, wavelengths are removed from what we see because each paint absorbs some of the wavelengths that the other paint reflects, leaving us with less wavelengths afterward.

Learn more about Subtractive mixing with the help of the given link:

brainly.com/question/1871483

#SPJ4

6 0

2 years ago

A wire is oriented along the x-axis. It is connected to two batteries, and a conventional current of 2.4 A runs through the wire

Deffense [45]

Answer:

$\vec{F}=0.40176 N \hat{k}$

Explanation:

To calculate the force we need to use this equation

$\vec{F}=\int\limits^L_0 {i(\vec{dl}\times\vec{B})}$

where L is the total length of the wire

So in this case the small element of current is

$\vec{dl} = dx \hat{i}$

Because x is the direction of the current flow.

As is said in the problem B is such that

$\vec{B} = B \hat{j} = 0.62\hat{j} [ T]$

so to use the equation above we first calculate the following cross product:

$\vec{dl}\times\vec{B}=dx \hat{i}\times B \hat{j} = Bdx\hat{k}$

so the force:

$F = \int\limits^L_0 {i(\vec{dl}\times\vec{B})}=\int\limits^L_0{iBdx\hat{k}}$

So here we use the fact that B=0 in any point of the x axis that is not $x^{'}=0.27 [m]$ , that means that we only need to do the integration between a very short distant behind the point $x^{'}=0.27 [m]$ and a very short distant after that point, meaning: