Answer:
The voltage drop across the bulb is 115 V
Explanation:
The voltage drop equation is given by:
Where:
ΔW is the total work done (4.6kJ)
Δq is the total charge
We need to use the definition of electric current to find Δq
Where:
I is the current (2 A)
Δt is the time (20 s)
Then, we can put this value of charge in the voltage equation.
Therefore, the voltage drop across the bulb is 115 V.
I hope it helps you!
