Question 1 :
m = mass of iron sample = 83
c = specific heat of iron sample = 0.450 J/g ⁰C
T₀ = initial temperature = 297 K
T = final temperature = 329 K
Q = heat lost
Heat lost is given as
Q = m c (T - T₀)
inserting the values
Q = (83) (0.450) (329 - 297) = 1195.2 J
Question 2 :
m = mass of sample = 59 g
c = specific heat of sample = ?
ΔT = change in temperature = 85 c
c = specific heat
Q = heat absorbed = 4814.4 J
Heat absorbed is given as
Q = m c
inserting the values
4814.4 = (59) (85) c
c = 0.96 J/g C
the sample is cholorofom
Question 3 :
m = mass of sample = 55 g
c = specific heat of sample = ?
T₀ = initial temperature = 78 c
T = final temperature = 95 c
Q = heat absorbed = 3908.3 J
Heat absorbed is given as
Q = m c (T - T₀)
inserting the values
3908.3 = (55) (95 - 78) c
c = 4.2 J/g C
the sample is water
