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pickupchik [31]
3 years ago
6

a lead block drops its temperature by 5.90 degrees celsius when 427 J of heat are removed from it. what is the mass of the block

?(unit=kg) IM GIVING 30 POINTS FOR THE CORRECT ANSWER
Physics
1 answer:
Airida [17]3 years ago
7 0

Answer:

577g

Explanation:

Given parameters:

Temperature change = 5.9°C

Amount of heat lost = 427J

Unknown:

Mass of the block = ?

Solution:

The heat capacity of a body is the amount of heat required to change the temperature of that body by 1°C.

                H =  m c Ф

  H is the heat capacity

 m  is the mass of the block

  c is the specific heat capacity

   Ф is the temperature change

Specific heat capacity of lead is 0.126J/g°C

   m = H / m Ф

   m = \frac{427}{0.126 x 5.9}  = 577g

Mass of the lead block is 577g

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