Idk no idea none zero sorry hope someone know more than me
You need to consider the following:
Me (mass of Earth) = 5.98 x 10^24 kg
<span>Ms (mass of Sun) = 1.99 x 10^30 kg </span>
<span>G = 6.67 x 10^-11 N </span>
<span>
Formula:
F = G * M1M2/r^2
</span><span>The ratio FT/F = 4.02x10^-4 / 14.8
= 2.72x10^-5
</span><span>
Since,
1/2.72x10^-5 = 36800
The fraction ratio is 1/36800
</span>= <span>9.56x10^17 N</span>
Consider the motion of the car before brakes are applied:
v₀ = maximum initial velocity of the car before the brakes are applied
t = reaction time = 0.50 s
x₀ = distance traveled by the car before brakes are applied
since car moves at constant speed before brakes are applied
Using the equation
x₀ = v₀ t
x₀ = v₀ (0.50)
Consider the motion after brakes are applied :
v₀ = initial velocity of the car before the brakes are applied
a = acceleration = - 10 m/s²
v = final velocity of the car after it comes to stop = 0 m/s
x = stopping distance = initial distance - distance traveled before applying the brakes = 38 - x₀ = 38 - v₀ (0.50)
Using the equation
v² = v²₀ + 2 a x
inserting the values
0² = v²₀ + 2 (- 10) (38 - v₀ (0.50))
v²₀ = 20 (38 - v₀ (0.50))
v₀ = 23 m/s
Answer
i'm not 100% sure but 1764
Explanation:
Work done = gravitational potential energy
Gravitational potential energy = mass(kg) × height(m) × gravitational field strength(N/kg)
We can assume that the student is on earth so the gravitational field strength is 9.8N/kg
So work done = 60 × 3×9.8
=1764
(if you need help calculating power but if you do just divide your answer by 12 and you will get 147)
