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irakobra [83]
3 years ago
6

If the 140 g ball is moving horizontally at 25 m/s , and the catch is made when the ballplayer is at the highest point of his le

ap, what is his speed immediately after stopping the ball
Physics
1 answer:
sweet [91]3 years ago
7 0

(.140*25)+(75*0)= 3.5

3.5 = (.140 + 75)v

(3.5)/(.140 + 75) = v = .04657

which rounds up to .05 m/s

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Name the missing force... Normal <br>   Spring <br>   Tension <br>   Air Resistance
Kay [80]

the missing force is spring force.

The object is hanging from the spring and the spring is stretched by some distance from its equilibrium position.  due to this stretch in the spring , a spring force starts acting on the object trying to regain its equilibrium position.

the spring force is given as

F = kx

where F = spring force ,k = spring constant , x = stretch in the spring.

the spring force balances the weight of the object in down direction and hence keeps the block from falling down.

4 0
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Which of the following is the proper unit for measuring power? Newton Joules Watts Meters
fredd [130]
The unit for power is Watts. the newton is a unit for force. joules for energy and meters for distance
3 0
3 years ago
What is the role of the neutral wire
lions [1.4K]

Answer:

The neutral wire is often confused with ground wire, but in reality, they serve two distinct purposes. Neutral wires carry currents back to power source to better control and regulate voltage. Its overall purpose is to serve as a path to return energy.

5 0
3 years ago
A car starts from rest and acquires a velocity of 50m/s in 3secs. Calculate i) acceleration ii) distance covered.
mafiozo [28]

Answer: 75.02 m

Explanation:

u = 0 ( starts from rest )

v = 50 m/s

t = 3 s

( i ) a = v - u / t

= 50 - 0 /3

= 16.67

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= 0 × 3 + 1/2 × 16.67 × 3 × 3

= <u>75.02 m</u>

Hope this helps...

4 0
3 years ago
The magnetic field at 8 cm distance from a long straight wire, carrying is 0.2x10^-5 T. How much is the electric current in the
FrozenT [24]

Answer:

The electric current in the wire is 0.8 A

Explanation:

We solve this problem by applying the formula of the magnetic field generated at a distance by a long and straight conductor wire that carries electric current, as follows:

B=\frac{2\pi*a }{u*I}

B= Magnetic field due to a straight and long wire that carries current

u= Free space permeability

I= Electrical current passing through the wire

a  = Perpendicular distance from the wire to the point where the magnetic field is located

Magnetic Field Calculation

We cleared (I) of the formula (1):

I=\frac{2\pi*a*B }{u} Formula(2)

B=0.2*10^{-5}  T = 0.2*10^{-5} \frac{weber}{m^{2} }

a  =8cm=0.08m

u=4*\pi *10^{-7} \frac{Weber}{A*m}

We replace the known information in the formula (2)

I=\frac{2\pi*0.08*0.2*10^{-5}  }{4\pi *10x^{-7} }

I=0.8 A

Answer: The electric current in the wire is 0.8 A

4 0
3 years ago
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