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Harlamova29_29 [7]
2 years ago
6

In AABC, AB = 3 and AC = 9. Find m28 to the nearest degree.52587218​

Mathematics
1 answer:
valentina_108 [34]2 years ago
5 0

Answer:

72°

Step-by-step explanation:

==>Given:

∆ABC

AB = Opposite side length = 9

AC = Adjacent side length = 3

==>Required:

The measure of angle B

==>Solution:

Since ∆ABC is a right angled triangle, and we are given two sides (opposite and adjacent sides), to find m<B, we'd use the trigonometry formula tan B = Opposite/Adjacent.

Thus,

tan B = 9/3

tan B = 3

B = tan^-1(3) = 71.5650512°

<B to the nearest degree ≈ 72°

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3 years ago
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Setler [38]

Answer:

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Step-by-step explanation:

(1)         7x + 8y = 20

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(3)                 y =  -⁹/₁₀     Substitute (3) into (1)

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      7x              =      29 - 18/10

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                       20      = 20

(2) 7(136/35) – 2(-⁹/₁₀)  = 29

       136/5    +    18/10 = 29

       136/5    +      ⁹/₅    = 29

                        145/5  = 29

                        29       = 29

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3 years ago
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