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Harlamova29_29 [7]
3 years ago
6

In AABC, AB = 3 and AC = 9. Find m28 to the nearest degree.52587218​

Mathematics
1 answer:
valentina_108 [34]3 years ago
5 0

Answer:

72°

Step-by-step explanation:

==>Given:

∆ABC

AB = Opposite side length = 9

AC = Adjacent side length = 3

==>Required:

The measure of angle B

==>Solution:

Since ∆ABC is a right angled triangle, and we are given two sides (opposite and adjacent sides), to find m<B, we'd use the trigonometry formula tan B = Opposite/Adjacent.

Thus,

tan B = 9/3

tan B = 3

B = tan^-1(3) = 71.5650512°

<B to the nearest degree ≈ 72°

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3 years ago
2 1/2 * 1 1/6=???<br>I need help can someone explain this for me?
Dovator [93]

Answer:

35/12

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
So this has to do with permutations and honestly I need an explanation on how I can figure these out.
AnnZ [28]
Well, the answer quite simple ....there are 4! ways to arrange these numbers...and as 4! = 4*3*2*1 = 24

hence 24 is the correct answer....


u can also remember it by theorem of multiplication as.....in first place (I.e. first code can be any no. out of 4,5,2&7 ....so 4*.....

as first place is acquired by a certain no. that leaves three no. to fill third place and when third place I'd occupied it leaves 2 numbers to fill second place and lastly only one no. to fill the last place .....so it's result will be like 4*3*2*1.



I know this is pretty much confusing ....but still I tried my best....

if anything troubles u here feel free to ask me
6 0
4 years ago
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