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Harlamova29_29 [7]
3 years ago
6

In AABC, AB = 3 and AC = 9. Find m28 to the nearest degree.52587218​

Mathematics
1 answer:
valentina_108 [34]3 years ago
5 0

Answer:

72°

Step-by-step explanation:

==>Given:

∆ABC

AB = Opposite side length = 9

AC = Adjacent side length = 3

==>Required:

The measure of angle B

==>Solution:

Since ∆ABC is a right angled triangle, and we are given two sides (opposite and adjacent sides), to find m<B, we'd use the trigonometry formula tan B = Opposite/Adjacent.

Thus,

tan B = 9/3

tan B = 3

B = tan^-1(3) = 71.5650512°

<B to the nearest degree ≈ 72°

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