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nekit [7.7K]
2 years ago
6

HELP ME PLS!!!

Mathematics
1 answer:
atroni [7]2 years ago
8 0

Answer:

A. This conclusion was drawn using the law of detachment

Step-by-step explanation:

Definition:

Law of Detachment

If p equals q and p is also true. Then q is true.

if a number is a whole number, then it is an integer.

3 is a whole number (true statement) , so it 3 is an integer. (must be true)

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The same Honey is sold in two different size jars. Large jar= 540g for £4.10 Small jar= 360g for £2.81. By considering the amoun
Ray Of Light [21]

Answer:

From our calculations the large jar is the best value for money because a penny buys more honey

Step-by-step explanation:

<h2>In this problem we are expected to determine which purchase of honey is the cheapest ? large jar or small jar ?.</h2><h2 />

We will determine which has the best value for money using the quantity a pound can purchase.  

firstly for the large jar.

if £4.10 will purchase 540g of honey then,

   £1.00 will purchase xg

cross multiplying to find x will have

x=  \frac{1.00*540g}{4.10}

x= 131.7grams

Hence for the large jar a penny would buy 131.7g of honey

secondly for the small jar

if £2.81 will purchase 360g of honey then,

   £1.00 will purchase xg

cross multiplying to find x will have

x=\frac{1.00*360g}{2.81}\\x= 128.1gram

Hence for the small jar a penny would buy 128.1g of honey

4 0
3 years ago
How can I solve this?
kogti [31]

Answer ok so lets say every 1/3 is one and a  half one-acre lawn, of course 2/3 would make 3 lawns, so maybe a full tank can cut 4 and a half lawns

Step-by-step explanation:

sorry if im wrong

7 0
2 years ago
Read 2 more answers
If s is an increasing function, and t is a decreasing function, find Cs(X),t(Y ) in terms of CX,Y .
Sedbober [7]

Answer:

C(X,Y)(a,b)=1−C(s(X),t(Y))(a,1−b).

Step-by-step explanation:

Let's introduce the cumulative distribution of (X,Y), X and Y :

F(X,Y)(x,y)=P(X≤x,Y≤y)

  • FX(x)=P(X≤x)
  • FY(y)=P(Y≤y).

Likewise for (s(X),t(Y)), s(X) and t(Y) :

F(s(X),t(Y))(u,v)=P(s(X)≤u

  • t(Y)≤v)
  • Fs(X)(u)=P(s(X)≤u)
  • Ft(Y)(v)=P(t(Y)≤v).

Now, First establish the relationship between F(X,Y) and F(s(X),t(Y)) :

F(X,Y)(x,y)=P(X≤x,Y≤y)=P(s(X)≤s(x),t(Y)≥t(y))

The last step is obtained by applying the functions s and t since s preserves order and t reverses it.

This can be further transformed into

F(X,Y)(x,y)=1−P(s(X)≤s(x),t(Y)≤t(y))=1−F(s(X),t(Y))(s(x),t(y))

Since our random variables are continuous, we assume that the difference between t(Y)≤t(y) and t(Y)<t(y)) is just a set of zero measure.

Now, to transform this into a statement about copulas, note that

C(X,Y)(a,b)=F(X,Y)(F−1X(a), F−1Y(b))

Thus, plugging x=F−1X(a) and y=F−1Y(b) into our previous formula,

we get

F(X,Y)(F−1X(a),F−1Y(b))=1−F(s(X),t(Y))(s(F−1X(a)),t(F−1Y(b)))

The left hand side is the copula C(X,Y), the right hand side still needs some work.

Note that

Fs(X)(s(F−1X(a)))=P(s(X)≤s(F−1X(a)))=P(X≤F−1X(a))=FX(F−1X(a))=a

and likewise

Ft(Y)(s(F−1Y(b)))=P(t(Y)≤t(F−1Y(b)))=P(Y≥F−1Y(b))=1−FY(F−1Y(b))=1−b

Combining all results we obtain for the relationship between the copulas

C(X,Y)(a,b)=1−C(s(X),t(Y))(a,1−b).

7 0
3 years ago
Ullmark 1 Bus
Vesna [10]

Answer: Option B) 7,214

Step-by-step explanation:

The value of the digit 2 in 5,426 is 20.

-In 2,843, the place value of 2 is 2000

- In 7,214, the place value of 2 is 200

- In 43,928, the place value of 2 is 20

- In 67,452, the place value of 2 is 2

So, since he place value of 2 in 7,214 is 200; and since 200 is ten times more than 20 (i.e 20 x 10 = 200)

Thus, the answer is 7214

3 0
3 years ago
a card is chosen from a standard deck, then a month of the year is chosen. find the probability of getting a face card and june​
Irina-Kira [14]

Answer:

Probability of chossing a face card and the month of june = 0.019

Step-by-step explanation:

Let A be the event that a face card is chosen from a deck of 52 cards

And

B be the event that a month is being chosen from 12 months of an year

So,

n(S)for A=52

n(S)for B=12

As a deck of card has total of 12 face cards so

P(A)=12/52

=3/13

P(B)=1/12

As both the events are independent, the probability of A and B is the product of both events’ probabilities.

P(A and B)= P(A)*P(B)

=3/13*1/12

=3/156

=0.019

4 0
3 years ago
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