A 60.0- kg dancer leaps 0.32 m high. With what momentum does he reach the ground

kakasveta [241]

Since the connection is in series, the current divider can be used. It's mathematical expression is In = (It Rt) / Rn. If the value for is solved, power dissipation can also be solved using P = I^2 R.
I = 0.47 A
A. P = (0.47)^2 (5) = 1.11 Watts
B. P = (0.47)^2 (9) = 2 Watts
C. P = VI = 16(0.47) 4.24 Watts

4 0

4 years ago

Read 2 more answers

Two charged particles are placed 2.0 meters apart. The first charge is +2.0 E-6 C, and the second charge is +4.0 E-6 C. What is

Anestetic [448]

The electrical force between the two charges can be calculated as +1.8×10⁻² N and its repulsive.

To find the electrical force, distance = 2 meters

charge q1 = 2×10⁻⁶ C

charge q2 = 4×10⁻⁶ C

<h3>Define coulomb's law and solve with formula.</h3>

The force of attraction or repulsion acting along a straight line between two electric charges is directly proportional to the product of the charges and inversely to the square of the distance between them.

Formula can be written as,

F = K ( q1q2 / r² )

F - electric force

k - Coulomb constant

q1, q2 - charges

r - distance of separation

Substituting the values in the formula,

F = 9 × 10⁹ Nm²/C² ( (2×10⁻⁶ C × 4×10⁻⁶ C) / (2²))

= 0.0179751

F = 1.8 × 10 ⁻² N.

As both the charges q1 and q2 are positive, the charges gets repulsive.

SO, the correct answer is Option A.

Learn more about coulomb's law,

brainly.com/question/506926

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8 0

2 years ago

An ideal gas, initially at a pressure of 11.2 atm and a temperature of 299 K, is allowed to expand adiabatically until its volum

Tju [1.3M]

Answer:

The pressure is $P_2 = 4.25 \ a.t.m$

Explanation:

From the question we are told that

The initial pressure is $P_1 = 11.2\ a.t.m$

The temperature is $T_1 = 299 \ K$

Let the first volume be $V_1$ Then the final volume will be $2 V_1$

Generally for a diatomic gas

$P_1 V_1 ^r = P_2 V_2 ^r$

Here r is the radius of the molecules which is mathematically represented as

$r = \frac{C_p}{C_v}$

Where $C_p \ and\ C_v$ are the molar specific heat of a gas at constant pressure and the molar specific heat of a gas at constant volume with values

$C_p=7 \ and\ C_v=5$

=> $r = \frac{7}{5}$

=> $11.2*( V_1 ^{\frac{7}{5} } ) = P_2 * (2 V_1 ^{\frac{7}{5} } )$

=> $P_2 = [\frac{1}{2} ]^{\frac{7}{5} } * 11.2$

=> $P_2 = 4.25 \ a.t.m$

8 0

3 years ago

The speedometer of your car measures average speed?

Ronch [10]

The speedometer of a car reads instantaneous speed

6 0

4 years ago

9. The Metro Rail makes a stop at NRG Stadium to pick up some Texans fans after the game. After

attashe74 [19]

Answer:

It takes the train 7.5 seconds to reach top speed

The train travels 112.5 meters before it reaches its top speed

Explanation:

The Metro Rail makes a stop at NRG Stadium to pick up some Texans

fans after the game

After all the passengers board, the train accelerates at a rate of 4 m/s²

to a top speed of 30 m/s

We need to find the train takes how many seconds to reach the

top speed

Given is:

→ The train start from rest, then its initial speed u = 0

→ It acceleration a = 4 m/s²

→ Its top speed v = 30 m/s

To find the time we can use this rule;

→ $t=\frac{v-u}{a}$

→ $t=\frac{30-0}{4}=\frac{30}{4}=7.5$ seconds

<em>It takes the train 7.5 seconds to reach top speed</em>

Now we need to find how far the train travels before reaches top speed

We can use this rule;

→ v² = u² + 2as, where s is the distance

→ v = 30 m/s , u = 0 , a = 4 m/s²

Substitute these values in the rule

→ (30)² = 0 + 2(4) s

→ 900 = 8 s

Divide both sides by 8

→ s = 112.5 m

<em>The train travels 112.5 meters before it reaches its top speed </em>

7 0

3 years ago