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o-na [289]
3 years ago
15

Which statements describe acceleration? Check all that apply.

Physics
1 answer:
barxatty [35]3 years ago
8 0

Answer:

A, C, D, and F

Explanation:

Hope this helps! Please Mark Brainliest

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If the mass of the earth and all objects on it were suddenly doubled, then the ________
krok68 [10]

Answer:

The force of universal gravitation between earth and all objects in it will be quadrupled

Explanation:

Newtons law of universal gravitation tell us the force of attraction between two bodies on the earth surface . This force is directly proportional to the product of the masses of the bodies and inversely proportional to their distance apart.

f is directly proportional to m1*m2

doubling these masses will be 2m1*2m2 = 4m1m2

if mas of earth is Me and mass of all objects is Mo

the f is proportional to Me*Mo

doubling the masses of the earth and all objects we have, 2Me*2Mo= 4MeMo

This means that doubling the masses of the earth and all objects on it will cause the force of gravitational attraction to be quadrupled.

3 0
3 years ago
What will be the answer??
AnnZ [28]
5-a).  Acceleration is a vector defined as the rate of change of velocity.
Its magnitude has units of [length/time²].  The SI unit is meter/second².
Its direction is the direction in which velocity is increasing. 

5-b).  The graph says that the object's speed is not changing.
When we look at any time, from zero to almost 50 minutes, the
object's speed is the same . . . 60 m/s .  This will make it easy.

There are 60 seconds in a minute, so 30 minutes = 1,800 seconds.
In every one of those seconds, the object covered 60 meters.
It travelled a total of (60 m/s)·(1,800 s) = 108,000 meters (108 km) .
8 0
4 years ago
A force of 20 N produces an acceleration of 10 m/s² in mass m1 and an acceleration of 5 m/s² in
Scrat [10]

Explanation:

F = 20N m= m1 a=10m/s²

m=m2 a=5m/s²

F = ma

<u>for the first one</u><u>:</u><u> </u>

f=m1 × a

20 = m1 ×10

20=10m1

m1=20/10

m1=2

<u>for</u><u> </u><u>the</u><u> </u><u>second</u><u> </u><u>one</u><u> </u><u>:</u>

f=m2×a

20=m2×5

m2= 20/5

m2= 4

since F=ma

F=(m1+m2) ×a

F =(4+2)×a

F =6×a

F=20(from the question above )

20=6×a

a=20/6

a=3.33

8 0
4 years ago
Read 2 more answers
(15 points)
vodomira [7]

Answer:

1. Decrease

2. Decrease

3. Stay the same

Explanation:

1. The more predators there are that eat the prey(cricket/frog), the less prey there will be.

2. The more the pollution effects them negatively, the more the population will die off.

3. The decrease of food may kill the population, but the increase of food does not effect the birth rate of the population.

4 0
3 years ago
A projectile is launched straight up from a height of 960 feet with an initial velocity of 64 ft/sec. Its height at time t is h(
Natasha2012 [34]

Answer:

a) t=2s

b) h_{max}=1024ft

c) v_{y}=-256ft/s

Explanation:

From the exercise we know the initial velocity of the projectile and its initial height

v_{y}=64ft/s\\h_{o}=960ft\\g=-32ft/s^2

To find what time does it take to reach maximum height we need to find how high will it go

b) We can calculate its initial height using the following formula

Knowing that its velocity is zero at its maximum height

v_{y}^{2}=v_{o}^{2}+2g(y-y_{o})

0=(64ft/s)^2-2(32ft/s^2)(y-960ft)

y=\frac{-(64ft/s)^2-2(32ft/s^2)(960ft)}{-2(32ft/s^2)}=1024ft

So, the projectile goes 1024 ft high

a) From the equation of height we calculate how long does it take to reach maximum point

h=-16t^2+64t+960

1024=-16t^2+64t+960

0=-16t^2+64t-64

Solving the quadratic equation

t=\frac{-b±\sqrt{b^{2}-4ac}}{2a}

a=-16\\b=64\\c=-64

t=2s

So, the projectile reach maximum point at t=2s

c) We can calculate the final velocity by using the following formula:

v_{y}^{2}=v_{o}^{2}+2g(y-y_{o})

v_{y}=±\sqrt{(64ft/s)^{2}-2(32ft/s^2)(-960ft)}=±256ft/s

Since the projectile is going down the velocity at the instant it reaches the ground is:

v=-256ft/s

5 0
3 years ago
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